so far i think you have the right thing going for you just remember soh cah tohstep-by-step explanation: sine over hypotenusecosine equals adjacenttangent over hypotenuse...Read More
correct choice is astep-by-step explanation: the equation of the line passing through the points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is[tex]\dfrac{x-x_1}{x_2-x_1}=\dfrac{...Read More