an airplane flies at an altitude of 36,000 km and is traveling at a velocity of 300.0 km/h to the north, but the tailwind is 20.0 km/h. what is the airplane's final velocity? (remember that velocity is a vector.)

Vectors quantity have magnitude and direction, which means that they can be solved arithmetically with their corresponding signs. In this case, we can simply add the two velocities to get for the final velocity of the plane. But first let us determine the signs of each velocity value.

As a reference, we take the direction of the plane to be going the positive y-axis. Therefore it is going up and positive. Now take note that the wind is a “tailwind” which means that the wind is going WITH the direction of the plane, therefore it is also a positive. Now knowing that, we can add the two:

Final velocity = 300 km / hr + 20 km / hr

Final velocity = 320 km / hr

If a plane has a velocity of 300 km/h and a tailwind of 20 km/h, then the vectors of both forces would add (assuming that the tailwind is blowing exactly at the airplanes back) to a total of 320 km/h. Hope it helps

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