, 28.10.2020romeojose2005

# The line segment joining the mid point of any side with the opssosite vertex is called? ​

## Answers jazmyn1314
A median:)
hope this helped! tesie

B D E

Step-by-step explanation: willowcollins3753

1. given equation x – 2 y = - 4 and points (0, 0)

let us rewrite equation in y = m x + b form:

y = 0.5 x + 2

a line parallel to the original line must have same slope m = 0.5, so the equation is:

y = 0.5 x + b

calculate for b given (0, 0):

0 = 0.5 (0) + b

b = 0

so the final equation is:

y = 0.5 x

2. the formula for perimeter is:

p = 2 l + 2 w

we measure any length and width using the distance formula.

length = sqrt [(-7 – 1)^2 + (-2 – 0)^2] = 8.2462

width = sqrt [(1 – 0)^2 + (0 – 4)^2] = 4.1231

so the perimeter is:

p = 2 (8.2462) + 2 (4.1231)

p = 24.7386 ~ 24.7

3 . d) aas congruence theorem

you can actually see that angle b and d are congruent, they have similar angle a, and similar side ac, so angle angle side congruence.

4. i think the correct answer is:

c) open the compass so that the compass point is on point q and the pencil point on point p. then place the compass point on point a and draw an arc through ​ ab−→−

5. the steps in order are arranged as follows:

a)put the compass point on e and the pencil point on f

c)draw a point anywhere and label it point g

e)put the compass point on g and and draw an arc

d)label any point on the arc as point h

b)use the straightedge to join points g and h

6. i believe the correct one is:

b) place the compass point on the midpoint of the line segment and open the compass so that the pencil point is on point s. draw an arc on each side of the segment.

7. the correct one is:

b) keep the same compass opening, place the compass point on b, and draw a circle.

8. c) open her compass to the length of eb and draw a circle centered at point e. marshallmattah

1. given equation x – 2 y = - 4 and points (0, 0)

let us rewrite equation in y = m x + b form:

y = 0.5 x + 2

a line parallel to the original line must have same slope

m = 0.5, so the equation is:

y = 0.5 x + b

calculate for b given (0, 0):

0 = 0.5 (0) + b

b = 0

so the final equation is:

y = 0.5 x

2. the formula for perimeter is:

p = 2 l + 2 w

we measure any length and width using the distance

formula.

length = sqrt [(-7 – 1)^2 + (-2 – 0)^2] = 8.2462

width = sqrt [(1 – 0)^2 + (0 – 4)^2] = 4.1231

so the perimeter is:

p = 2 (8.2462) + 2 (4.1231)

p = 24.7386 ~ 24.7

3 . d) aas congruence theorem

you can actually see that angle b and d are congruent,

they have similar angle a, and similar side ac, so angle angle side congruence.

4. i think the correct answer is:

c) open the compass so that the compass point is on point

q and the pencil point on point p. then place the compass point on point a and

draw an arc through ​ ab−→−

5. the steps in order are arranged as follows:

a)put the compass point on e and the pencil point on f

c)draw a point anywhere and label it point g

e)put the compass point on g and and draw an arc

d)label any point on the arc as point h

b)use the straightedge to join points g and h

6. i believe the correct one is:

b) place the compass point on the midpoint of the line

segment and open the compass so that the pencil point is on point s. draw an

arc on each side of the segment.

7. the correct one is:

b) keep the same compass opening, place the compass point

on b, and draw a circle.

8. c) open her compass to the length of eb and draw

a circle centered at point e.

hope this hjoe523

see below. × signifies a wrong choice; → signifies a correct one

Step-by-step explanation:

× Jorge should graph in the vertical line with values of –4 for the line of reflection. (The line of reflection is horizontal.)

→ Jorge could count how far each pre-image point is from the line of reflection along the perpendicular from the point to the line of reflection.

× Jorge could count how far each vertex of the figure is from the y-axis and count the same distance on the other side. (He could do this pointless exercise, but it has no relation to the problem. The y-axis (x=0) is not the line of reflection.)

→ Jorge will not move any point that lies on the line of reflection. (All points on the line of reflection are reflected to themselves.)

→ Jorge could check his work by seeing if each segment joining a pre-image point with its image has the midpoint on the line of reflection. (This is what is meant by "line of reflection.")

× Jorge could check his work by making sure that the image has the same orientation as the original. (A reflected image as an orientation opposite that of the original, a fact you see every time you look in a mirror.)

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