, 28.10.2020tiffany1711

# There is a temperature change of 3 °C in the room when 1.5 kg of water flows through the radiator each second.The specific heat capacity of water is 4200 J/kg°C.i.Calculate the amount of energy given to the room by the 1.5 kg of water as it passesthrough the radiator.Show your working and write down the unit.​

## Answers alexiagreen1212

this could be newton#'s law of cooling. the cooling curve is exponential studybug7952
Does this your question? angelica3752

Explanation:

Q = mcT

where,

Q is heat(energy)

m is mass

c is specific heat capacity

T is change in temperature

so,

Q= 1.5kg x 4200 J/kg.C x 3C

Q = 18900J of energy tonimgreen17p6vqjq

18900J

Explanation:

energy = Temperature change * Mass * Specific Heat Capacity

3*1.5*4200=18900

=18900J

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