There is a temperature change of 3 °C in the room when 1.5 kg of water flows through the radiator each second.
The specific heat capacity of water is 4200 J/kg°C.
i.
Calculate the amount of energy given to the room by the 1.5 kg of water as it passes
through the radiator.
Show your working and write down the unit.​

Answers

this could be newton#'s law of cooling. the cooling curve is exponential

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Explanation:

                   Q = mcT

where,

          Q is heat(energy)

          m is mass

           c is specific heat capacity

           T is change in temperature

so,

      Q= 1.5kg x 4200 J/kg.C x 3C

       Q = 18900J of energy

18900J

Explanation:

energy = Temperature change * Mass * Specific Heat Capacity

3*1.5*4200=18900

=18900J



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