x = (6.00 m/s^2)t^2,

where x is in meters and t is in seconds.

(a) determine its position (in m) at t = 3.20 s.

(b) determine its position (in m) at t = (3.20 s) + δt.

(c) evaluate the limit of δx δt as δt approaches zero to find the velocity (in m/s) at t = 3.20 s.

The earths atmosphere is made up of nitrogen and oxygensolids turning into gases is called sublimation.

Learned about life itself

38.4 m/s

Explanation:

a) at t = 3.2s.

b) at t = 3.2 + Δt.

c) As Δt approaches 0. We can find the velocity by the ratio of Δx/Δt

As Δt approaches 0, v = 38.4 + 0 = 38.4 m/s

38.4 m/s

Explanation:

a) at t = 3.2s.

b) at t = 3.2 + Δt.

c) As Δt approaches 0. We can find the velocity by the ratio of Δx/Δt

As Δt approaches 0, v = 38.4 + 0 = 38.4 m/s

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