When a moving car is brought to a stop with the brakes, its acceleration vector is 29. (a) in the same direction as its velocity vector b) in the opposite direction as its velocity vector c) equal to zero (d) directed downward


The unit vector is given by the following formula:
 a '= (a) / (lal)
 a: vector a
 lal: Vector module a
 We are looking for the module:
 lal = root ((- 15) ^ 2 + (8) ^ 2)
 lal = 17
 Same direction:
 a = -15i + 8j
 The unit vector is:
 a '= (1/17) * (- 15i + 8j)
 Opposite direction:
 a = 15i - 8j
 The unit vector is:
 a '= (1/17) * (15i - 8j)
 a unit vector that has the same direction as the vector a is:
 a '= (1/17) * (- 15i + 8j)
 a unit vector that has the opposite direction of the vector a is:
 a '= (1/17) * (15i - 8j)

idk lol

Step-by-step explanation:

ty 4 the points doe

Hello There!

When an object moves in uniform circular motion, the direction of its acceleration is directed toward the center of its circular path.

Uniform circular motion is a certain object or thing that that is traveling in a circular path. The reason why "uniform" is there because a part of it has to stay constant.

C) is directed toward the center of its circular path.


Uniform Circular Motion happens when its trajectory is a circumference and its velocity modulus remains constant over time.

In our daily life we often observe the movement made by fans, car wheels and also by the blender. These are all examples of devices that use MCU.

Within the study of uniform circular motion there is the presence of centripetal acceleration, ie when there is speed variation there is acceleration.

Centripetal acceleration is always directed to the center of the circumference. It does not change the modulus of velocity and its mathematical representation is given by the equation:

                                 acp = v2 / R or acp = ω2 R

To develop this problem we will apply the concepts related to the kinematic equations of motion, specifically that of acceleration. Acceleration can be defined as the change of speed in an instant of time, mathematically this is

\vec{a} = \frac{\vec{v_2}-\vec{v_1}}{\Delta t}

If a mobile is decreasing its speed (it is slowing down), then its acceleration is in the opposite direction to the movement. This would imply that the acceleration vector is opposite to the velocity vector.

Therefore the correct answer is B.

Do you know the answer?

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