Use the image below to answer the following question: a right triangle is shown. the two angles that are not 90 degrees are marked x and y. the leg across from angle y measuring 12, another leg across from angle x measuring 16, and the hypotenuse measuring 20. what relationship do the ratios of sin x° and cos y° share?
the ratios are opposites (16 over 20 and negative 16 over 20)
the ratios are both identical (16 over 20 and 16 over 20)
the ratios are both negative (negative 16 over 20 and negative 16 over 20)
the ratios are reciprocals (16 over 20 and 20 over 16)

Answers

The sine of the measure of an angle in a right triangle, is the ratio of the opposite side of that angle, to the hypotenuse.

The cosine of the measure of an angle in a right triangle, is the ratio of the adjacent side of that angle, to the hypotenuse.

According to these, we have:

\displaystyle{ \sin(x^{\circ})= \frac{6}{10}

and

\displaystyle{ \sin(y^{\circ})= \frac{6}{10} .

Thus, the ratios of both are identical ( \frac{6}{10} \ and \ \frac{6}{10}  )
The complete question in the attached figure

we know that

sin x°=12/13
cos y°=12/13
that means angle x and angle y are complementary angles---------> (x°+y°)=90°

so
sin x°=cos y°

hence
the ratios are both identical

the answer is
the ratios are both identical (12 over 13 and 12 over 13)

What relationship do the ratios of sin x° and cos y° share?  the ratios are both identical (12 over
Recall that the sin of an angle is the opposite side over the hypothenuse and the cos of an angle is the adjacent side of the hypothenuse.applying the above principles to the given angle we get the ratios: \sin x= \frac{4}{5}\\\cos y= \frac{4}{5}\text{ too} so  \sin x=\cos y means that the ratio are identical 
I think your answer is The ratios are reciprocals ( 12/13 and 12/13 )

sin x = o/h   cos y = a/h  

sin x =12/13  cos y = 12/13

when its sin x the opposite is 12 and the hypotenuse is 13, and when its cos y the adjacent is 12 and the hypotenuse is still 13 (^>^)
 

The ratios are reciprocals ( -12/13 and 12/13)

Step-by-step explanation:

I took a test and got it right

The ratios are both identical (16 over 20 and 16 over 20)

Step-by-step explanation:

we know that

In the right triangle of the figure

sin(x)=\frac{16}{20} ----> opposite side angle x divided by the hypotenuse

cos(y)=\frac{16}{20} ----> adjacent side angle y divided by the hypotenuse

therefore

sin(x)=cos(y)

Because  x and y are complementary angles

The answer you are looking for is The 12 over 13 and 12over 13

idk

step-by-step explanation:

A. ratios are both identical (9over 15 and 9over 15)

Step-by-step explanation:

There is no graph attached but I assume it is a right triangle with hypotenuse of 15 and a side of 9 opposite to angle x, and adjacent to angle y

then sinx=cosy= 9/15

A. ratios are both identical (9over 15 and 9over 15)

  The ratios are both identical ( 3 over 5 and 3 over 5 )

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you that ...

  Sin = Opposite/Hypotenuse

  sin(x°) = 3/5

and

  Cos = Adjacent/Hypotenuse

  cos(y°) = 3/5

__

  sin(x°) = cos(y°) = 3/5



Do you know the answer?

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