, 30.07.2021emont9829

# Find the sum of the second multiple of 9 and the fifth multiple of 6.​

If three consecutive values add to 567 the middle value must be 567/3 = 189
Since the values are multiples of 9, the other values must be 189 - 9 and 189 + 9

The three values are 180, 189, 198

Step-by-step explanation:

divide 63 from 9

see below

Step-by-step explanation:

We can write the first number as 9n because it is a multiple of 9, and the second number will be 9(n + 1). We can write:

9n + 9(n + 1) = 63 because they have a sum of 63.

9n + 9n + 9 = 63

18n + 9 = 63

18n = 54

n = 3

This means that the first number is 9 * 3 = 27 and the second is 9 * (3 + 1) = 9 * 4 = 36.

n=200-0 /9=200/9=22.222

n~22terms

a=9

d=9

Sn=(n/2)(2a+(n-1)d)

S22=(22/2)(2*9+(22-1)9)

S22=11(18+(21)9)

S22=11(18+189)

S22=11(207)

S22=2277

27

36

Step-by-step explanation:

So if they are consecutive multiples of 9, just make the numbers you multiply by x and x + 1

9x + 9x + 9 = 63

18x = 54

x = 3

3 * 9 = 27

4 * 9 = 36

CHECK:

27 + 36 = 63

7

Step-by-step explanation:

Divide 63 by 9 which is 7

Work-63÷9=7

Step-by-step explanation:

18 and 30

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Mathematics, 21.06.2019, lnbrown9018