For f (x)= -x + 8, what is the value of x for which f(x) = 9?

Answers

(A)

x=-4

(B)

g(x)=\frac{3x-1}{x+4}+4

(C)

x=-17

Step-by-step explanation:

we are given

f(x)=\frac{3x-1}{x+4}

(a)

we know that

any function is undefined when denominator =0

so, we can set denominator =0

and then we can solve for x

x+4=0

x=-4

So, it does not have solution at x=-4

(b)

If g(x) is a vertical shift up 4 units from f(x)

Whenever we shift vertically upward by 'a' units , we always add 'a' to y-value

so, we get

g(x)=f(x)+4

we get

g(x)=\frac{3x-1}{x+4}+4

Graph:


(C)

we can set g(x)=8

and then we can solve for x

8=\frac{3x-1}{x+4}+4

8\left(x+4\right)=3x-1+4\left(x+4\right)

8x+32=7x+15

x=-17


Consider the function fx=3x-1/x+4. (a) at which value of x will the function not have a solution?  e

x=-1

Step-by-step explanation:

f (x)= -x + 8

Let f(x) = 9

9 = -x+8

Subtract 8 from each side

9-8 = -x+8-8

1 = -x

Multiply each side by -1

-1 = x



Do you know the answer?

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