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# Martin is making a candy that contains 90% milk chocolate and the rest caramels. the candy has 3 pounds of caramels. part a: write an equation using one variable that can be used to find the total number of pounds of milk chocolate and caramels in the candy. define the variable used in the equation. part b: how many pounds of milk chocolate are present in the candy? show your work.

We know that a candy contains 90% milk chocolate and it has 3 pounds of caramels.Part A:An equation:0.9 x + 3 = x,where x is the weight of the candy ( in pounds ).Part B :0.9 x + 3 = xx - 0.9 x = 30.1 x = 3x = 3 : 0.1x = 30 pounds.Milk chocolate.0.9 * 30 = 27 pounds.
If the candy contains 90% milk chocolate, then it contains 10% caramel.
There are 3 lbs of caramel. So.. 10% of the total amount of candy is 3 lbs.

0.10x = 3
x = 3/0.10
x = 30so there are 30 lbs candy in total

The variable x stands for total # of lbs of candy

If there is 30 lbs of candy, and 3 lbs are caramel, then (30 - 30) = 27 lbs are milk chocolate

The equation using one variable that can be used to find the total number of pounds of milk chocolate and caramels in the candy is

x= Weight of candy in pounds

0.9x = Weight of milk chocolate.

Step-by-step explanation:

Given, Martin is making a candy that contains 90% milk chocolate and the rest caramels. The candy has 3 pounds of caramels.

Let x= Weight of candy in pounds

Then, 0.9x = Weight of milk chocolate.

Then, According to the question

So, Weight of milk chocolate. =

Hence,  the equation using one variable that can be used to find the total number of pounds of milk chocolate and caramels in the candy is

a) 0.1 x = 3 pounds

b) 27 pounds

Explanation:

Since we have given that

Let the number of pounds of candy be s

Let the number of pounds of milk chocolate be

Let the number of pounds of caramels be

a) Write an equation using one variable that can be used to find the total number of pounds of milk chocolate and caramels in the candy.

To find the number of pounds of caramels , the equation will be

b) Number of pounds of milk chocolate are present in the candy is given by

This the concept of algebra, let the amount of milk m and that of caramel be c. Total amount of chocolate will be p.
The amount of caramel=3 pounds;
The amount of milk=90%=0.9/0.1*3=27 pounds milk
Therefore the total amount of milk in candy will be:
m=0.9p
The total amount of caramel will be:
c=0.9p

Percentage of Caramel in chocolate is 10%. The amount of milk will therefore be:
0.9/0.1*3=27  pounds

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