Let x be the number of rocks that George have at first.

First, George have x rocks. Then, he gets 5 new rocks. So, we have:

Next, half of his rock collection is given to Susan.

Susan got 36 rocks, so the equation is

First, George have x rocks. Then, he gets 5 new rocks. So, we have:

Next, half of his rock collection is given to Susan.

Susan got 36 rocks, so the equation is

Do 36 times 2, this is George’s whole collection before he gave anything to Susan. Then subtract 5, and he had that many

Let

x--------> amount of starting rocks George had

we know that

------> equation that could be used to determine how many rocks George started with

Solve for x

Multiply by both sides

Subtract both sides

therefore

the answer Part a) is

The equation that could be used to determine how many rocks George started with is

the answer Part b) is

Hi There!

C) 1/2 (x+5) = 36

Step-by-step explanation:

Multiply 2 too both sides:

1/2 * 2 (x + 5) = 36 * 2

(x + 5) = 72

Subtract 5 too both sides:

x + 5 - 5 = 72 - 5

Simplify:

x = 67

Hope This Helps :)

C) 1/2 (x+5) = 36

George started with 70 rocks

Step-by-step explanation:

Given: After getting 5 new rocks, George gave half of his rock collection to Susan. If George gave Susan 36 rocks.

Let "x" be number of rocks that George started with.

After getting 5 new rocks.

He will have (x + 5) rocks.

George gave half of his rock collection to Susan.

(x + 5) /2 has given to Susan which is 36

Which can be written as

This can be rewritten as:

The answer is C)

To find the number of rocks George started with, we need to solve the above equation.

Multiply by both sides by 2, we get

(x + 2) = 2(36)

x + 2 = 72

Subtracting 2 from both sides, we get

x + 2 - 2 = 72 - 2

x = 70

So, George started with 70 rocks

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