Tell whether the graph of the quadratic function y=-x^2-10x+1 opens upward or downward.
a. because , the parabola opens upward.
b. because , the parabola opens downward.
c. because , the parabola opens upward.
d. because , the parabola opens downward.

Answers

It opens downwards so it looks like this “n”. That is because a in the formula is a negative number in this situation
It opens downward because the coefficient (-2) is a negative number. The parabola would open downwards.
C. If the first coefficient is negative, then the graph opens downwards

Vertex: (-4,9)

y-intercept: (0,-7)

The graph opens downward

Attached is an image of the graph, hope this helps!


Find the vertex of the graph of the quadratic function. Determine whether the graph opens upward or

Hope that helps.

I think this is a partial ans.


The graph of a quadratic equation always has an extreme location (maximum or minimum). state whether

down

Step-by-step explanation:

y = -3x^2 +x +1

The coefficient of the x^2 term is negative so it opens facing down

X^2 coeffient

- means down

+ mean up

-3x is a negative coefficient so it faces downward. If it was positive, then it would face upward.

 Graph attached.

Step-by-step explanation:

It is easier to figure it out if you can see it.

Also easier if you rewrite the equation in quadratic form:

y = 4x² + 4x + 5


Tell whether the graph of the quadratic function  y − 4x2 = 4x + 5 opens upward or downward and whet
For
y=ax^2+bx+c
if a>0, then the paraobla opens up
if a<0, then parabola opens down

given
y=-1x^2-10x+1
-1<0
opens down because leading coefinet is negative

either B or D, they are identical (looks like something was omited)
For
y=ax^2+bx+c
if a>0, then the paraobla opens up
if a<0, then parabola opens down

given
y=-1x^2-10x+1
-1<0
opens down because leading coefinet is negative

either B or D, they are identical (looks like something was omited)


Do you know the answer?

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