Tell whether the graph of the quadratic function y=-x^2-10x+1 opens upward or downward.
a. because , the parabola opens upward.
b. because , the parabola opens downward.
c. because , the parabola opens upward.
d. because , the parabola opens downward.

It opens downwards so it looks like this “n”. That is because a in the formula is a negative number in this situation

It opens downward because the coefficient (-2) is a negative number. The parabola would open downwards.

C. If the first coefficient is negative, then the graph opens downwards

Vertex: (-4,9)

y-intercept: (0,-7)

The graph opens downward

Attached is an image of the graph, hope this helps!

Hope that helps.

I think this is a partial ans.

down

Step-by-step explanation:

y = -3x^2 +x +1

The coefficient of the x^2 term is negative so it opens facing down

X^2 coeffient

- means down

+ mean up

-3x is a negative coefficient so it faces downward. If it was positive, then it would face upward.

 Graph attached.

Step-by-step explanation:

It is easier to figure it out if you can see it.

Also easier if you rewrite the equation in quadratic form:

y = 4x² + 4x + 5

For
y=ax^2+bx+c
if a>0, then the paraobla opens up
if a<0, then parabola opens down

given
y=-1x^2-10x+1
-1<0
opens down because leading coefinet is negative

either B or D, they are identical (looks like something was omited)

For
y=ax^2+bx+c
if a>0, then the paraobla opens up
if a<0, then parabola opens down

given
y=-1x^2-10x+1
-1<0
opens down because leading coefinet is negative

either B or D, they are identical (looks like something was omited)