a. because , the parabola opens upward.

b. because , the parabola opens downward.

c. because , the parabola opens upward.

d. because , the parabola opens downward.

It opens downwards so it looks like this “n”. That is because a in the formula is a negative number in this situation

It opens downward because the coefficient (-2) is a negative number. The parabola would open downwards.

Vertex: (-4,9)

y-intercept: (0,-7)

The graph opens downward

Attached is an image of the graph, hope this helps!

down

Step-by-step explanation:

y = -3x^2 +x +1

The coefficient of the x^2 term is negative so it opens facing down

X^2 coeffient

- means down

+ mean up

-3x is a negative coefficient so it faces downward. If it was positive, then it would face upward.

Graph attached.

Step-by-step explanation:

It is easier to figure it out if you can see it.

Also easier if you rewrite the equation in quadratic form:

y = 4x² + 4x + 5

For

y=ax^2+bx+c

if a>0, then the paraobla opens up

if a<0, then parabola opens down

given

y=-1x^2-10x+1

-1<0

opens down because leading coefinet is negative

either B or D, they are identical (looks like something was omited)

y=ax^2+bx+c

if a>0, then the paraobla opens up

if a<0, then parabola opens down

given

y=-1x^2-10x+1

-1<0

opens down because leading coefinet is negative

either B or D, they are identical (looks like something was omited)

y=ax^2+bx+c

if a>0, then the paraobla opens up

if a<0, then parabola opens down

given

y=-1x^2-10x+1

-1<0

opens down because leading coefinet is negative

either B or D, they are identical (looks like something was omited)

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