Write two mixed numbers where the lcd is 12, but the product of the denominators is not 12.

The prime factorization of 12 is
  12 = 2²×3

To find denominators suitable for your purpose, you need to group the factors
  {1, 2, 2, 3}
into two groups with different products that share at least one of the numbers that is not 1.

For example, your grouping could be (2, [2), 3], where a 2 is shared. That is, your denominators could be 2*2=4 and 2*3=6.
Another possible grouping is (1, [2), 2, 3], giving rise to denominators of 2 and 12.
Yet another is (1, [3), 2, 2], for denominators of 3 and 12.

Using the first grouping, a pair of mixed numbers matching your requirement might be
  1 3/4, 5 1/6

Step-by-step explanation:

The prime factorization of 12 is

 12 = 2²×3

To find denominators suitable for your purpose, you need to group the factors

 {1, 2, 2, 3}

into two groups with different products that share at least one of the numbers that is not 1.

For example, your grouping could be (2, [2), 3], where a 2 is shared. That is, your denominators could be 2*2=4 and 2*3=6.

Another possible grouping is (1, [2), 2, 3], giving rise to denominators of 2 and 12.

Yet another is (1, [3), 2, 2], for denominators of 3 and 12.

Using the first grouping, a pair of mixed numbers matching your requirement might be

 1 3/4, 5 1/6

1 3/4 and 5 1/6 maybe

1 3/4 and 5 1/6 Hope this helps!

A number is said to be mixed if it can be written in the form of .

We have to write two mixed numbers where the LCD is 12, but the product of the denominators is not 12

   

Here, the product of denominators is , 6 ×4=24

But, their LCD is

  6=3×2

  4=2×2

LCD=3×2×2

      =12

Hpefully ill get it right cause i love helping people but try 2,4,5,6