Acylindrical basin is 2 feet tall and has a diameter of 5 feet, as shown. if the basin is completely filled with water, how much water will it hold? round the answer to the nearest tenth of a foot.


Acylindrical basin is 2 feet tall and has a diameter of 5 feet, as shown. if the basin is completely

Answers

Find Radius:

Radius = Diameter ÷ 2

Radius = 5 ÷ 2 = 2.5 feet

-

Find Volume:

Volume of a cylinder = πr²h

Volume = π (2.5)² (2) = 39.3 ft³ (nearest tenth)

-

39.3 ft³

39.3 ft^3

Step-by-step explanation:

The cylindrical basin has a height of 2 ft and a diameter of 5 ft.

To find the amount of water that will completely fill up the basin, we simply need to find the volume of the basin.

The volume of a cylinder is given as:

V = \pi r^2h

where r = radius of the basin (half the diameter) = 2.5 ft

h = height of the basin

Hence, the volume is:

V = \pi * 2.5^2 * 2

V = 39.27 ft^339.3 ft^3

The cylindrical basin can hold up to 39.3 ft^3 of water.

39.3

Step-by-step explanation:

got it right on edge

39.3 ft3

Step-by-step explanation:

ON EDGE

The formula for solving the volume of a cylindrical basin is equal to V=pi*r²*h 
39.3 Ft
The formula for solving the volume of a cylindrical basin is equal to V=pi*r²*h 
39.3 Ft
The formula for solving the volume of a cylindrical basin is equal to V=pi*r²*h where "h" represents the height and "r" for the radius. Hence, in the given problem we have h=2ft and r=diameter/2.
r=5/2
r=2.5 ft
Solving for the volume:
V=3.1416*2.5²*2
V=39.27 cubic feet
If 1 cubic feet can hold 7.5 gallons, therefore the cylindrical basin can hold
#gallon=39.27*(7.5/1)
#gallon=294.525 gallons
The formula for solving the volume of a cylindrical basin is equal to V=pi*r²*h where "h" represents the height and "r" for the radius. Hence, in the given problem we have h=2ft and r=diameter/2.
r=5/2
r=2.5 ft
Solving for the volume:
V=3.1416*2.5²*2
V=39.27 cubic feet
If 1 cubic feet can hold 7.5 gallons, therefore the cylindrical basin can hold
#gallon=39.27*(7.5/1)
#gallon=294.525 gallons


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