Write the equation of the circle with center (−3, 2) and (6, 4) a point on the circle.

Answers

What is the inequality?

question is incomplete.

(x-h)^2+(y-k)^2=r^2
center is (h,k) and radius is r

so

given center=(-3,2)=(h,k)
(x-(-3))^2+(y-2)^2=r^2
(x+3)^2+(y-2)^2=r^2
find r^2
ok, (6,4) is a point
sub 6 for x and 4 for y and evaluate

(6+3)^2+(4-2)^2=r^2
(9)^2+(2)^2=r^2
81+4=r^2
85=r^2

the equation is
(x+3)^2+(y-2)^2=85
Radius=sqrt(2^2+9^2)
r=9.22
equation
(x+3)^2+(y-2)^2=9.22^2
(x+3)^2+(y-2)^2=85


Do you know the answer?

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