8x(7x – 1) –1(7x – 1)

Answers

you dont use the distributive property

(8x-1)(7x-1)

then you foil it and combine like terms

The factorization of the polynomial 56x^2-8x-7x+1 is (8x-1)(7x-1)

Step-by-step explanation:

We need to Complete the steps to factor 56x^2-8x-7x+1 by grouping.

After grouping:

(56x^2-8x) + (-7x + 1)

Factor the GCF from each group.

8x(7x-1)-1(7x-1)\\

Use the distributive property.

(8x-1)(7x-1)

So, the factorization of the polynomial 56x^2-8x-7x+1 is (8x-1)(7x-1)

Keywords: factorization by grouping

Learn more about factorization by grouping at:

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(8x-1)(7x-1)

Step-by-step explanation: Got it right on the warm-up

(8x-1)(7x-1) The question leaves you with the partially factored equation: 8x(7x-1) - 1(7x-1) look at the partially factored equation, you'll see that both terms have (7x-1) as one of their factors. take that (7x-1) as a factor and divide both terms by (7x-1), giving you (8x(7x-1) - 1(7x-1)) / (7x-1) The (7x-1) factors cancel out, leaving you with (8x - 1) So your 2 factors are (7x-1) and (8x-1). Looking at the available options, the only correct one is (8x-1)(7x-1)

(8x – 1)(7x – 1)

(8x-1)(7x-1) The question leaves you with the partially factored equation: 8x(7x-1) - 1(7x-1) Now if you look at the partially factored equation, you'll see that both terms have (7x-1) as one of their factors. So let's take that (7x-1) as a factor and divide both terms by (7x-1), giving us (8x(7x-1) - 1(7x-1)) / (7x-1) The (7x-1) factors cancel out, leaving us with (8x - 1) So our 2 factors are (7x-1) and (8x-1). Looking at the available options, the only correct one is (8x-1)(7x-1)

Answer is in the photo. I couldn't attach it here, but uploaded it to a file hosting. link below! Good Luck!

cutt.ly/rzNrBcz



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