y= -3x+2

y= -2/3x

-4y= 6x + 4

2y + 3x-5 =0

I’m not sure if this is how you’re supposed to write the summary statement, but I got the answer of (2x+3)(x-1)(-2/(x-2)) (see photo to see my work

Number 3, 4, and 5 are polynomials

Step-by-step explanation:

Polynomials do not contain fractions as in expression 1 nor radicals as in expression 2.

Also they do not contain negative exponents as in expression 6.

Polynomials contain integer coefficients only.

D

Step-by-step explanation:

To determine the point that is not on the graph substitute the x- coordinate into h(x) and if the value obtained is equal to the y- coordinate of the point then it lies on the graph

h(- 3) = 3(- 3)² - 5(- 3) + 4 = 27 + 15 + 4 = 46

(- 3, 46) ← lies on the graph

h(- 2) = 3(- 2)² - 5(- 2) + 4 = 12 + 10 + 4 = 26

(- 2, 26)← lies on the graph

h(- 1) = 3(- 1)² - 5(- 1) + 4 = 3 + 5 + 4 = 12

(- 1, 12) ← lies on the graph

h(- 4) = 3(- 4)² - 5(- 4) + 4 = 48 + 20 + 4 = 72 ≠ 46

(- 4, 46) ← does not lie on the graph

2x²+ x - 3 +

Step-by-step explanation:

We have to divide the polynomial (2x³- 3x²- 5x + 4) by (x - 2) using synthetic division.

2 | 2 -3 -5 4

× 4 2 -6

-------------------------

2 1 -3 -2

Now we will form the expression in the form of fraction again

2x²+ 1.(x) - 3 +

Therefore, 2x²+ x - 3 + will be the answer.

1. (-1,4)(1,4)(-2,4)(2,4) is a function because it has no repeating x values.

2. A is a subset of B because everything in A is in B ?? not sure exactly what u r looking for

3. a(b*c) = (a*b)cassociative property

4. the intersection of A and C is { empty set } because they have no letters in common

5. range is all ur y valuesso the range of G is { 0,2,6,7 }

6. the union of B and C is { a,b,e,g,i,l,o,r,u }

7. set A is an empty set

8. the union of A and B is { a,b,e,g,i,l,o r,u }

9. 5(3 + 2) = 15 + 10distributive property

10. f(x) = 3x - 1f(-2) = 3(-2) - 1 = -6 - 1 = -7

g(x) = -x + 6g(5) = -5 + 6 = 1

f(-2) + g(5) = -7 + 1 = -6 <==

11. { -6,-5,-4,-3,-2,-1 }

2. A is a subset of B because everything in A is in B ?? not sure exactly what u r looking for

3. a(b*c) = (a*b)cassociative property

4. the intersection of A and C is { empty set } because they have no letters in common

5. range is all ur y valuesso the range of G is { 0,2,6,7 }

6. the union of B and C is { a,b,e,g,i,l,o,r,u }

7. set A is an empty set

8. the union of A and B is { a,b,e,g,i,l,o r,u }

9. 5(3 + 2) = 15 + 10distributive property

10. f(x) = 3x - 1f(-2) = 3(-2) - 1 = -6 - 1 = -7

g(x) = -x + 6g(5) = -5 + 6 = 1

f(-2) + g(5) = -7 + 1 = -6 <==

11. { -6,-5,-4,-3,-2,-1 }

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