Recall the Spice Girls Emporium example. A list of useful information is given below. n = 36 The sample mean income is $41,100 The population standard deviation is estimated to be $4,500 What if we wanted to change our level of confidence to be 99%? What would our new margin of error be? Your answer should be given as an integer.

Answers

i dont know nkw

step-by-step explanation:

kenffledkedncklzkdfeserw

the thermometer is precise but not accurate

step-by-step explanation:

Margin of error = 1932

Step-by-step explanation: Margin of Error is the amount of variation a survey's results have. In other words, it is understood as the measure of variation one can see if the same survey was taken multiple times.

Margin of error is calculated as z\frac{\sigma}{\sqrt{n}}

z is z-score related to the percentage of confidence, in this z = 2.576

σ is population standard deviation

n is how many individuals are there in the sample or population

With a new level of confidence of 99%:

ME = 2.576.\frac{4500}{\sqrt{36}}

ME = 2.576(750)

ME = 1932

The new margin of error would be 1932.



Do you know the answer?

Other questions on the subject: Mathematics

Mathematics, 22.06.2019, ajam71501
15 DEGREESStep-by-step explanation:OK SO BASICALLY,  USING THE EXTERIOR ANGLES THEOREM, YOU FIND THAT 9x = 5x + something. That something is 4x so:9x = 5x + 4xTHEN YOU FIND THAT 8x...Read More
3 more answers