Aline parallel to the line y=4x - 3 that passes through point (3,13)

Answers

The slope of line L is

 =  \frac{ - 3 - 3}{2 -  - 1}  =   \frac{ - 6}{3}  =  - 2
Since the line is parallel to L , it also has the same gradient,

The equation is

y =  - 2(x - 3) + 3
y =  - 2x + 6 + 3
y =  - 2x + 9

x=3

Step-by-step explanation:

Plot the point, then follow it down till you reach the x axis.

Or

Simply write "x=" then whatever the first number in your parenthesis is.

The Answer is: y = 2x - 3

Step-by-step explanation:

Given points: (3, 3) and (4, 5)

Find the slope, m:

m = y - y1/(x - x1)

m = 3 - 5/(3 - 4)

m = -2/-1 = 2

Use the Point Slope form of the equation:

y - y1 = m(x - x1)

y - 5 = 2(x - 4)

y - 5 = 2x - 8

y = 2x - 8 + 5

y = 2x - 3

Proof:

f(3) = 2(3) - 3

= 6 - 3 = 3, giving (3, 3)

Step-by-step explanation:

Solve by doing y-y1 Over

x-x1 to find m. Pick either set of points and set up the equation as y=mx+b. So if you were to pick 3,3 as your set of points you would set up the equation like this: 3=m(that’s what you find earlier in the problem) (3) +b. Hope this helps in not good at explaining

Step-by-step explanation:

Let the equation if the line be y = mx + c

since the line is parallel to y = (smt-your question isn't complete), their gradients/slope must be the same (aka m = __)

sub (3, 3):

3 = __(3) + c

c = __

therefore, the equation of the line is y = __x + __

This is a question on coordinate geometry. If you wish to venture further into it/understand this topic better, you may want to follow my Instagram account (learntionary), where I post some of my own notes on certain topics and also some tips that may be useful to you :)

-2/5

Step-by-step explanation:

First, let's find the slope of line s using slope formula:

m_s = \frac{8-3}{5-3} = \frac{5}{2}

The slope of a line perpendicular to any is the negative reciprocal of the slope of that line. So, since line s has a slope of 5/2, slope of line t is:

m_t = -\frac{2}{5}

  y -3 = (1/2)(x -3)

Step-by-step explanation:

The given line has a slope that is ...

  rise / run = (-2)/(1) = -2

The perpendicular line will have a slope that is the negative reciprocal of that:

  m = -1/(-2) = 1/2

In point-slope form, the equation of the line with slope m through point (h, k) is ...

  y -k = m(x -h)

The line with slope 1/2 through point (3, 3) will have equation ...

  y -3 = (1/2)(x -3)


19. what is the equation of the line perpendicular to line l that passesthrough point (3, 3)? ​
So you know the new equation must have the same slope as the old equation since they're parallel to one another. Next just simply take the slope and the point given and plug them into the point-slope formula and you have your new equation:
y-y1=m(x-x1) --- Point-Slope Formula
y-13=4(x-3)
y=4x+1 --- Answer


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