two positive, consecutive, odd integers have a product of 143. complete the equation to represent finding x, the greater integer.​

Answers

x(x –  2 ) = 143

 

What is the greater integer?

13

Two positive, consecutive, odd integers have a product of 143.

 

Complete the equation to represent finding x, the greater integer.

x(x –  2) = 143

 

What is the greater integer?

13

the greater integrer is X=13

Step-by-step explanation:

1. Two consecutive odd integer numbers must be mandatory separated  by two numbers, like 3 and 5. those numbers (3 and 5) are two consecutive odd integers and we can see the difference between them is 2. Another example, 11 and 13 are two consecutive odd integers and the difference between them is also 2.

So, we have:

x(x-2)=143

here, x is representing the first number and (x-2) is represent the second consecutive number.

If we try to isolate x from x(x-2)=143, we will get the possible values of 11 and 13. You can check the multiply of them is 143. so the two numbers are :

X=13  and  X=13 - 2 = 11  where 13 is the greater integrer

The answer is 13

Step-by-step explanation:

Two positive and consecutive old numbers are x and x - 2.

=> x(x - 2) = 143

=> x^2 - 2x - 143 = 0

=> x^2 + 11x - 13x - 143 = 0

=> x(x + 11) - 13(x + 11) = 0

=> (x + 11)(x - 13) = 0

=>  x = -11 (invalid)

or x = 13 (valid), the remaining number is 13 - 2 = 11

=> The two numbers are 11 and 13, and the greater number is 13.

Hope this helps!

:)

Step-by-step explanation:

x and x+2 are the numbers

x(x+2)=143

x²+2x-143=0

x²+13x-11x-143=0

x(x+13)- 11(x+13)=0

(x+13). (x-11)=0

x+13=0. x=-13

x-11=0. x=11

Step-by-step explanation:

Answers:

k = 13The smallest zero or root is x = -10

Work Shown:

note: you can write "x^2" to mean "x squared"

f(x) = x^2+3x-10

f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5

f(x+5) = (x^2+10x+25)+3(x+5)-10

f(x+5) = x^2+10x+25+3x+15-10

f(x+5) = x^2+13x+30

Compare this with x^2+kx+30 and we see that k = 13

Factor and solve the equation below

x^2+13x+30 = 0

(x+10)(x+3) = 0

x+10 = 0 or x+3 = 0

x = -10 or x = -3

The smallest zero is x = -10 as its the left-most value on a number line.

13

Step-by-step explanation:

x(x-2)=143 x^2-2x-143=0 (x+11)(x-13)=0 so x must -11 or 13 but it’s positive so it is 13

11,13

Step-by-step explanation:

let the one of the number is x,then other of its consecutive odd number will be x+2

now their product will be

x(x+2)=143

i.e, x^2+2x=143

i.e, x^2+2x-143=0

i.e, x^2+13x-11x-143=0

i.e,x(x+13)-11(x+13)=0

i.e, (x+13)(x-11)=0

either x+13 =0,

or, x-11=0

i.e, x=11

it's positive number so x= -13 will be neglected

so the number will be 11

other one will be 11+2=13

✌️:)

11, 13

Explanation:

The problem is asking us to find two consecutive integers that have a product of 143. If we call x the greatest of the two numbers, the other number can be written as (x-2). Their product must be equal to 143, so we have

x(x-2)=143

Let's solve the equation:

x^2 -2x -143 =0

this is a second-oder equation that has two real solutions: x=13 and x=-11. We are not interested in the negative solution, so our solution is x=13. Therefore, the two numbers are

x=13

x=13-2=11

(x)(x+2)=143
the greater is x+2
or if it x(x-2)=143 then x is the greater one


Do you know the answer?

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