given that there are two triangles j'k'l' and jkl>
the former is got by dilating the second one.
when drawn on a grid, (graph paper) coordinates of vertices of first triangle is
(6,12)j, (9,6)k and (12,9)l
side jk has length = distance between j and k
side j'k'=distance between j' and k'
ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.
hence scale factor of 1/3 is used to get j'k'l'from jkl
in simplified version it would be x ≤-4
multiply each term in x ≤-4 by -1
the given angle is
1 cycle is equal to 2π radians. so 4π will be equal to two cycles.
5.166667π-4π = 1.166667π
hence, this angle goes a little more than negative x axis.
hence, the reference angle is 0.166667π radians.
1 radian = 57.2958 degrees
now, in degrees, this should be equals to 9.55 degrees.