i. f(3) when f(x) = 2x + 2

ii. f-1(4) when f(x) = (3x-4)/5

iii. y + 10 = 2y + 1

F(x) = 2x + 2find f(3)

f(3) = 2(3) + 2

f(3) = 6 + 2

f(3) = 8

f(x) = (3x - 4)/5find f^-1(4)

y = (3x - 4)/5...swap the variables

x = (3y - 4)/5 ...solve for y

5x = 3y - 4

5x + 4 = 3y

(5x + 4)/3 = y

f^-1(x) = (5x + 4)/3for f(4)

f(4) = (5(4) + 4)/3

f(4) = (20 + 4)/3

f(4) = 24/3

f(4) = 8

y + 10 = 2y + 1

y - 2y = 1 - 10

-y = -9

y = 9

so 1 and 2 have the same result...8

f(3) = 2(3) + 2

f(3) = 6 + 2

f(3) = 8

f(x) = (3x - 4)/5find f^-1(4)

y = (3x - 4)/5...swap the variables

x = (3y - 4)/5 ...solve for y

5x = 3y - 4

5x + 4 = 3y

(5x + 4)/3 = y

f^-1(x) = (5x + 4)/3for f(4)

f(4) = (5(4) + 4)/3

f(4) = (20 + 4)/3

f(4) = 24/3

f(4) = 8

y + 10 = 2y + 1

y - 2y = 1 - 10

-y = -9

y = 9

so 1 and 2 have the same result...8

None, because

Step-by-step explanation:

I. When then

II. Find the inverse function for the function

Thus,

III. Solve the equation

f(3)=2*3+2=8

f-1=(3x-4)/5-1=(3x-4-5)/5=(3x-9)/5 => f-1(4)=[(3*4)-9]/5=3/5

y+10=2y+1 => y=9

I. ) f ( 3 ) = 36 + 2 = 8

II. ) f ( x ) = ( 3 x - 4 ) / 5

y = ( 3 x - 4 ) / 5

5 y = 3 x - 4

5 y + 4 = 3 x

x = ( 5 y + 4 ) / 3

f-1(x ) = ( 5 x + 4 ) /3

f-1(4) = ( 20 + 4 ) / 3 = 24/3 = 8

III. ) y + 10 = 2 y + 1

- y = - 9

y = 9

The same result have I. and II.

II. ) f ( x ) = ( 3 x - 4 ) / 5

y = ( 3 x - 4 ) / 5

5 y = 3 x - 4

5 y + 4 = 3 x

x = ( 5 y + 4 ) / 3

f-1(x ) = ( 5 x + 4 ) /3

f-1(4) = ( 20 + 4 ) / 3 = 24/3 = 8

III. ) y + 10 = 2 y + 1

- y = - 9

y = 9

The same result have I. and II.

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