Assume that 25​% of people have sleepwalked. Assume that in a random sample of 1470 ​adults, 377 have sleepwalked.
a. Assuming that the rate of 25​% is​ correct, find the probability that 377 or more of the 1470 adults have sleepwalked.
b. Is that result of 377 or more significantly​ high?
c. What does the result suggest about the rate of 25​%?

Answers

d. 8

step-by-step explanation:

the given radical expression is:

\sqrt{16}\times \sqrt{4}

we can rewrite this as:

(16)^{\frac{1}{2}\times (4)^{\frac{1}{2}

we express as square numbers to get;

(4^2)^{\frac{1}{2}\times (2^2)^{\frac{1}{2}

the exponents will now cancel out to give.

4\times2=8

the correct answer is d

What is the value of the radical expression shown below
The correct answer is c

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

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step-by-step explanation:

What is the last question i don’t see it?


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