Based on the side lengths given (a, b, and c), which triangles are right triangles?
a = 4,b = 6,c = 8
a = 6,b = 8,c = 10
a = 5,b = 6,c = 16 square root
a = 6,b = 9,c = 12

Answers

There are no side lengths given.
The Correct Answers are Options 2 & 3

2.) a=6, b=8, c=10
3.) a=5, b=6, c= square root of 61
By Pythagoras theorem
2 is the answer
As 6^2=8^2=10^2
3 is the answer
As 5^2+6^2=square root of 61

So 2 and 3 are the answers
B and C are the right triangles!
B and C are the correct triangles.
A=6, b=8, c=10 is the only one i believe. Sorry if I'm wrong. 

to determine if a triangle is a right triangle, use the pythagorean theorem

a^2 +b^2 = c^2

if this is true is it a right triangle

B & C

Step-by-step explanation:

Use the Pythagorean Theorem:   a^2 + b^2 = c^2

A) 18^2 + 24^2 = 2,088   |   42^2 = 1,764     [NOT A]

B) 33^2 +56^2 = 4,225   |   65^2 = 4,225     [B IS CORRECT]

C) 19^2 + 180^2 = (32,761) = 181^2 = (32,761)     [C IS CORRECT]

D) 3^2 + 4^2 = 25  |   7^2 = 49     [NOT D]

I hope this helped you ! In return, please deem this the most brainliest answer.

a=6, b=8, c=10

Step-by-step explanation:

a=6, b=8, c=10

6² + 8² = 36 + 64 = 100 = 10²

a = 6, b = 8, and c = 10.

Step-by-step explanation:

You can easily use the Pythagorean Theorem to solve all of these.

a = 4; b = 6; c = 8... 4^2 + 6^2 = 16 + 36 = 52. 8^2 = 64. 52 is not equal to 64, so the first choice is not a right triangle.

a = 6; b = 8; c = 10... Well this is a multiple of the 3-4-5 Pythagorean triple, so this is a right triangle.

a = 5; b = 6; c = 761... 5^2 + 6^2 = 25 + 36 = 61. 761^2 = 579121, which is not equal to 61, so the third choice is not a right triangle.

a = 6; b = 9; c = 12... 6^2 + 9^2 = 36 + 81 = 117. 12^2 = 144, which is not equal to 117, so the fourth choice is not a right triangle.

The only case where there is a right triangle is the second choice, where a = 6, b = 8, and c = 10.

Hope this helps!



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