You'll need to write an equation for this. Let's name our adults y, and the children x. So x+y=2200, as 2200 people went to the fair and people are either x or y. We also know that kid admission is 1.50, and adult admission is 4, so use y and x to make an equation for this. 1.5x+4y=5050 as 5050 was collected. So, you have the system of equations

x+y=2200

1.5x+4y=5050

I'll use substitution to solve. Isolate x in the top equation by subtracting y. so x+y-y=2200-y, and x=2200-y. Substitute this value for x into the second equation, so 1.5(2200-y)+4y=5050. Use the distributive property for the parentheses, so 3300-1.5y+4y=5050. Add together the y values of -1.5 and 4. You get 2.5, so 3300+2.5y=5050. Subtract 3300 from each side of the equation to begin isolating 2.5y, which gives you 1750. Divide 1750 by 2.5 to isolate y, which gives you 700. So you know y=700, so 700 adults attended. You know y=700 so put that into the first equation.

x+700=2200.

Isolate x by subtracting 700 from both sides, which gives you x=1500. So, 700 adults and 1500 children attended.

x+y=2200

1.5x+4y=5050

I'll use substitution to solve. Isolate x in the top equation by subtracting y. so x+y-y=2200-y, and x=2200-y. Substitute this value for x into the second equation, so 1.5(2200-y)+4y=5050. Use the distributive property for the parentheses, so 3300-1.5y+4y=5050. Add together the y values of -1.5 and 4. You get 2.5, so 3300+2.5y=5050. Subtract 3300 from each side of the equation to begin isolating 2.5y, which gives you 1750. Divide 1750 by 2.5 to isolate y, which gives you 700. So you know y=700, so 700 adults attended. You know y=700 so put that into the first equation.

x+700=2200.

Isolate x by subtracting 700 from both sides, which gives you x=1500. So, 700 adults and 1500 children attended.

To solve this problem, you'll need to create a system of equations and then solve for the variables. For my two equations, x = # of children and y = # of adults

We know from the problem that the total amount of people who attended the fair is 2200, so that tells us that the number of children (x) plus the number of adults (y) will give us 2200. So, that's our first equation.

x + y = 2200

We also know that the total amount of money collected was $5050. This tells us that the number of children's tickets sold (1.50 * x) plus the number of adult's tickets sold (4 * y) will give us $5050. So, that's our second equation.

1.50x + 4y = 5050

Now, you take both equations and solve for the variables.

x + y = 2200

1.50x + 4y = 5050

x + y = 2200

x = -y + 2200

1.50(-y + 2200) + 4y = 5050

-1.50y + 3300 +4y = 5050

3300 + 2.5y = 5050

2.5y = 1750

y = 700

Now that you know that y =700, you plug that information into either of the two equations and solve for x. I'm going to use the first equation because it's easier.

x + y = 2200

x + 700 = 2200

x = 1500

So, x = 1500 and y = 700

We know from the problem that the total amount of people who attended the fair is 2200, so that tells us that the number of children (x) plus the number of adults (y) will give us 2200. So, that's our first equation.

x + y = 2200

We also know that the total amount of money collected was $5050. This tells us that the number of children's tickets sold (1.50 * x) plus the number of adult's tickets sold (4 * y) will give us $5050. So, that's our second equation.

1.50x + 4y = 5050

Now, you take both equations and solve for the variables.

x + y = 2200

1.50x + 4y = 5050

x + y = 2200

x = -y + 2200

1.50(-y + 2200) + 4y = 5050

-1.50y + 3300 +4y = 5050

3300 + 2.5y = 5050

2.5y = 1750

y = 700

Now that you know that y =700, you plug that information into either of the two equations and solve for x. I'm going to use the first equation because it's easier.

x + y = 2200

x + 700 = 2200

x = 1500

So, x = 1500 and y = 700

I would write systems of equations for this problem.

1.5x + 4y = 5050

x + y = 2200

From there solve the system of equations where x represents the number of children and y represent the number of adults.

x + y = 2200

x = 2200 - y

Plug "x" into the other system of equation.

1.5(2200-y) + 4y = 5050

3300 - 1.5y + 4y = 5050

2.5y = 1750

y = 700

Since you have the value for y, solve for x.

x + y = 2200

x + 700 = 2200

x = 1500

So, the solution is: 1500 children and 700 adults attended.

Just to check our answers:

1.5x + 4y = 5050

1.5(1500) + 4(700) = 5050

2250 + 2800 = 5050

5050 = 5050

1.5x + 4y = 5050

x + y = 2200

From there solve the system of equations where x represents the number of children and y represent the number of adults.

x + y = 2200

x = 2200 - y

Plug "x" into the other system of equation.

1.5(2200-y) + 4y = 5050

3300 - 1.5y + 4y = 5050

2.5y = 1750

y = 700

Since you have the value for y, solve for x.

x + y = 2200

x + 700 = 2200

x = 1500

So, the solution is: 1500 children and 700 adults attended.

Just to check our answers:

1.5x + 4y = 5050

1.5(1500) + 4(700) = 5050

2250 + 2800 = 5050

5050 = 5050

700 adults and 1500 children

Step-by-step explanation:

Let the number of adults be x and the number of children be y , then

x + y = 2200 equation 1

4x + 1.5y = 5050 equation 2

solving the system of linear equation by substitution method , from equation 1 make x the subject of the formula , that is

x = 2200 - y equation 3

substitute x = 2200 - y into equation 2 , that is

4 ( 2200 - y ) + 1.5y = 5050

8800 - 4y + 1.5y = 5050

8800 - 2.5y = 5050

2.5y = 8800 - 5050

2.5y = 3750

y = 3750/2.5

y = 1500

substitute y = 1500 into equation 3 , we have

x = 2200 - y

x = 2200 - 1500

x = 700

Therefore , 700 adults and 1500 children entered

$1.50C + $4A= $5050

C + A = 2200

-4(C + A = 2200)

-4C - 4A = -8800

1.50C+4A = 5050

-2.5C =- 3750

-2.5C/-2.5 =- 3750/-2.5

C = 1500

C + A = 2200

1500 + A =2200

1500 - 1500 + A = 2200 - 1500

A = 700

CHECK

$1.50C + $4A= $5050

$1.50(1500) + $4(700)= $5050

$2250 +$2800 =$5050

$5050 = $5050

C + A = 2200

1500 + 700 =2200

2200 = 2200

C + A = 2200

-4(C + A = 2200)

-4C - 4A = -8800

1.50C+4A = 5050

-2.5C =- 3750

-2.5C/-2.5 =- 3750/-2.5

C = 1500

C + A = 2200

1500 + A =2200

1500 - 1500 + A = 2200 - 1500

A = 700

CHECK

$1.50C + $4A= $5050

$1.50(1500) + $4(700)= $5050

$2250 +$2800 =$5050

$5050 = $5050

C + A = 2200

1500 + 700 =2200

2200 = 2200

Step-by-step explanation:This is definitely exponential growth. The ruling formula will have the form y = c·(2)^(nx), where the "2" comes from "double," c is the initial value and...Read More

3 more answers

might be the correct answer will be question number 2...Read More

1 more answers

arrange the equations with like terms in columns. analyze the coefficients of x or y. add the equations and solve for the remaining variable. substitute the value into either equa...Read More

1 more answers

2.56 is the width of the gardenstep-by-step explanation:...Read More

1 more answers

pakistan's principal natural resources are arable land and water. about 25% of pakistan's agriculture accounts for about 21% [1] of gdp and employs about 43% of the labour force. i...Read More

1 more answers

1. A table can be a helpful thing to model the rate of change. It can be used by making an x and y column and listing each number underneath it like so: x y1 22 4And so on. The rat...Read More

2 more answers

- Grace sent short msg of 60 words, if she paid 40k for the first 12 wor...
- The ratio of I's to M's 4:4 2. the ratio of S's to P's 2:11 3. the rat...
- Varadha bought two bags of rice of weights 45 kg and 63 kg. Find the m...
- Office workers were asked how long it took them to travel to work one...
- Write the equations, after translating the graph of y = |x+2|: one uni...
- U and v are position vectors with terminal points at (-1, 5) and (2, 7...
- Ms. Brown needs 8 eggs in order to make 2 cakes. What is the total num...
- Find the value of x. X=8 X=10 X=16 X=20...
- Rory records the percentage of battery life remaining on his phone thr...
- Jerry wants to gravel an area represented by a square with side length...