The ages of three siblings are all consecutive
integers. the sum of their ages is 39. how old is
the youngest sibling?

Answers

9

Step-by-step explanation:

im not 100% sure but i gave it a shot

12, the youngets would be 12

12 year old is the youngest sibling

Step-by-step explanation:

Given: The ages of three siblings are all consecutive integers.

           The sum of sibling´s age is 39.

Now, finding the age of youngest sibling.

Lets assume the age of youngest sibling be "x"

As given, The ages of three siblings are all consecutive integers.

∴ Age of 2nd sibling will be (x+1)

 Age of 3rd sibling will be (x+2)

next, forming an equation for the sum of sibling´s age.

x+(x+1)+(x+2)= 39

Opening the parenthesis

x+x+1+x+2= 39

3x+3= 39

Subtracting both side by 3

3x= 39-3

3x= 36

Dividing both side by 3

x= \frac{36}{3}

∴ x= 12

Subtituting the value of x to find the age of other sibling

∴Youngest sibling age= 12 years

2nd sibling age= 13 years

3rd sibling age= 14 years

Hence, The youngest sibling is 12 years old.

12 year old is the youngest sibling

Step-by-step explanation:

Given: The ages of three siblings are all consecutive integers.

           The sum of sibling´s age is 39.

Now, finding the age of youngest sibling.

Lets assume the age of youngest sibling be "x"

As given, The ages of three siblings are all consecutive integers.

∴ Age of 2nd sibling will be (x+1)

 Age of 3rd sibling will be (x+2)

next, forming an equation for the sum of sibling´s age.

x+(x+1)+(x+2)= 39

Opening the parenthesis

x+x+1+x+2= 39

3x+3= 39

Subtracting both side by 3

3x= 39-3

3x= 36

Dividing both side by 3

x= \frac{36}{3}

∴ x= 12

Subtituting the value of x to find the age of other sibling

∴Youngest sibling age= 12 years

2nd sibling age= 13 years

3rd sibling age= 14 years

Hence, The youngest sibling is 12 years old.



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