Jupiter’s average distance from the sun is 7.8 x 10^8 kilometers. the ratio comparing jupiter’s distance from the sun to a meteorite’s distance from the sun is 3 x 10^-2. what is the meteorite’s distance from the sun?

Answers

answer: i believe it’s 245.04

step-by-step explanation:

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

Meteorite’s distance from the sun is 2.6 \times 10^{10} kilometers

Solution:

Given that,

\text{Jupiters average distance from the Sun } = 7.8 \times 10^8 \text{ kilometer }

Also, given that,

The ratio comparing Jupiter’s distance from the Sun to a meteorite’s distance from the sun is 3 \times 10^{-2}

Which means,

\frac{\text{Jupiters distance from the Sun}}{\text{meteorite’s distance from the sun}} = 3 \times 10^{-2}

Substitute the given value in above fraction,

\frac{7.8 \times 10^8}{\text{meteorite’s distance from the sun}} = 3 \times 10^{-2}

Solve for meteorite’s distance from the sun

\text{Meteorites distance from the sun} = \frac{7.8 \times 10^8}{3 \times 10^{-2}}\\\\\text{Meteorites distance from the sun} = \frac{2.6 \times 10^8}{10^{-2}}\\\\\text{Use the law of exponent }\\\\\frac{a^m}{a^n} = a^{m-n}\\\\\text{Meteorites distance from the sun} =2.6 \times 10^{8-(-2)}\\\\\text{Meteorites distance from the sun} = 2.6 \times 10^{8+2}\\\\\text{Meteorites distance from the sun} =2.6 \times 10^{10}\\\\

Thus, meteorite’s distance from the sun is 2.6 \times 10^{10} kilometers

Meteorite’s distance from the sun is 2.6 \times 10^{10} kilometers

Solution:

Given that,

\text{Jupiters average distance from the Sun } = 7.8 \times 10^8 \text{ kilometer }

Also, given that,

The ratio comparing Jupiter’s distance from the Sun to a meteorite’s distance from the sun is 3 \times 10^{-2}

Which means,

\frac{\text{Jupiters distance from the Sun}}{\text{meteorite’s distance from the sun}} = 3 \times 10^{-2}

Substitute the given value in above fraction,

\frac{7.8 \times 10^8}{\text{meteorite’s distance from the sun}} = 3 \times 10^{-2}

Solve for meteorite’s distance from the sun

\text{Meteorites distance from the sun} = \frac{7.8 \times 10^8}{3 \times 10^{-2}}\\\\\text{Meteorites distance from the sun} = \frac{2.6 \times 10^8}{10^{-2}}\\\\\text{Use the law of exponent }\\\\\frac{a^m}{a^n} = a^{m-n}\\\\\text{Meteorites distance from the sun} =2.6 \times 10^{8-(-2)}\\\\\text{Meteorites distance from the sun} = 2.6 \times 10^{8+2}\\\\\text{Meteorites distance from the sun} =2.6 \times 10^{10}\\\\

Thus, meteorite’s distance from the sun is 2.6 \times 10^{10} kilometers



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