Jerry started doing sit-ups every day. the first day he did 13 sit-ups. every day after that he did 2 more sit-ups than he had done the previous day. today jerry did 29 sit-ups. write an equation that could be solved to find the number of days jerry has been doing sit-ups, not counting the first day. let  n  represent the number of days.

an equation that can jerry to find the number of days he has been doing sit-ups is given by

Answers

Y=13+2n
29-13=16
16÷2 =8 days

An equation that can help Jerry to find the number of days he has been doing sit-ups is   \frac{a_{n} -13}{2} +1 = n

Step-by-step explanation:

First day = 13

Second day =  first day + 2 = 13 +2 =15

Third day  =  second day + 2 =  17

Fourth day = Third day +2  = 19

So,

13 , 15 , 17, 19, 21, 23 ...........

The common difference is 2

By using arithmetic series

a_{n}  = 13  + (n-1)d

where

a_n is the number of sit-ups done on the nth day

n is  number of the days

d is the difference

Now

a_{n}  = 13  + (n-1)(2)

a_{n} -13 = (n-1)(2)

\frac{a_{n} -13}{2} = (n-1)

\frac{a_{n} -13}{2} +1 = n

An equation that can help Jerry to find the number of days he has been doing sit-ups is   \frac{a_{n} -13}{2} +1 = n

Step-by-step explanation:

First day = 13

Second day =  first day + 2 = 13 +2 =15

Third day  =  second day + 2 =  17

Fourth day = Third day +2  = 19

So,

13 , 15 , 17, 19, 21, 23 ...........

The common difference is 2

By using arithmetic series

a_{n}  = 13  + (n-1)d

where

a_n is the number of sit-ups done on the nth day

n is  number of the days

d is the difference

Now

a_{n}  = 13  + (n-1)(2)

a_{n} -13 = (n-1)(2)

\frac{a_{n} -13}{2} = (n-1)

\frac{a_{n} -13}{2} +1 = n



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