tan(t) =

1

8

,

terminal point of t is in quadrant iii

12/13

Step-by-step explanation:

Use a Pythagorean identity that has tangent.

tan²(t) + 1 = sec²(t)

(5/12)² + 1 = sec²(t)

25/144 + 1 = sec²(t)

169/144 = sec²(t)

sec(t) = ±13/12

cos(t) = ±12/13

Since 0 < t < π/2, cos(t) > 0.

cos(t) = 12/13

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