Dis the midpoint of ef.
ed = 4x + 6
df = 7x -9
find ef.

Answers

I'm assuming you meant to write 7x-3 instead... If so, AB=22.

Because K is the midpoint of AB,AK must equal KB.

Set the two equal to each other and solve for x...

4x+3=7x-3 \\
4x+6=7x \\
6=3x \\
x=2

Now plug 2 in for x in either AK or KB.

AK=4(2)+3=8+3=11

or

KB=7(2)-3=14-3=11

Now we know half of the length of AB. Multiplying 11 by 2 will give us the full length, which is 22.

The line segment EF=11x-3

Step-by-step explanation:

Given that D is the midpoint of EF , ED=4x+6  and DF=7x-9

To find the EF :

Let EF is a line segment  and D its midpoint(given)

EF=ED+DF

=(4x+6)+(7x-9)

=4x+6+7x-9 ( adding the like terms )

=11x-3

Therefore EF=11x-3

Therefore the line segment EF=11x-3

The line segment EF=11x-3

Step-by-step explanation:

Given that D is the midpoint of EF , ED=4x+6  and DF=7x-9

To find the EF :

Let EF is a line segment  and D its midpoint(given)

EF=ED+DF

=(4x+6)+(7x-9)

=4x+6+7x-9 ( adding the like terms )

=11x-3

Therefore EF=11x-3

Therefore the line segment EF=11x-3



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