Find the area of the rectangle , i put a pic .


Find the area of the rectangle , i put a pic .

Answers

There are 4 rectangles in the ArrayList shapes. ArrayLists start counting at 0 so when index is 3, dataRecord will be the 4th rectangle. The length and width of the 4th rectangle in shapes are both 4 so the area is 16 and the perimeter is 16. The answer is 3.
C.  Area of rectangle is A=L X W

If the length is 5 times bigger and the width is 5 times bigger, than the area is 25 times bigger

Check the attached image for code screenshot and output.

Explanation:

      Rectangle.cpp

#include "Rectangle.h"

Rectangle::Rectangle() {

       length = 0;

       width = 0;

}

Rectangle::Rectangle(double newLength, double newWidth) {

       length = newLength;

       width = newWidth;

}

void Rectangle::setLength(double l) {

       length = l;

}

void Rectangle::setWidth(double w) {

       width = w;

}

double Rectangle::getLength() {

       return length;

}

double Rectangle::getWidth() {

       return width;

}

double Rectangle::computeArea() {

       return length * width;

}

double Rectangle::computePerimeter() {

       return 2 * (length + width);

}

Rectangle Rectangle::operator++ () {

       length++;

       width++;

       return *this;

}

Rectangle Rectangle::operator++ (int) {

       Rectangle r(length, width);

       ++length;

       ++width;

       return r;

}

Rectangle Rectangle::operator-- () {

       if(length > 0) {

               length--;

       }

       if(width > 0) {

               width--;

       }

       return *this;

}

Rectangle Rectangle::operator-- (int) {

       Rectangle r(length, width);

       if(length > 0) {

               length--;

       }

       if(width > 0) {

               width--;

       }

       return r;

}

Rectangle Rectangle::operator- (Rectangle other) {

       

       if(length > other.length && width > other.width) {

               length--;

               width--;

       } else {

               cout << "invalid operation. Subtrated Rectangle is bigger" << endl;

       }

       return *this;

}

bool Rectangle::operator==(Rectangle other) {

       return (length == other.length) && (width == other.width);

}

bool Rectangle::operator!=(Rectangle other) {

       return (length != other.length) || (width != other.width);

}

void Rectangle::printDetails() {

       cout << "Rectangle Report" << endl;

       cout << "Dimensions: " << length << " X " << width << endl;

       cout << "Area: " << computeArea() << endl;

       cout << "Perimeter: " << computePerimeter() << endl;

       cout << "" << endl;

}

        Rectangle.h

#include<iostream>

#include<iomanip>

using namespace std;

class Rectangle {

       double length, width;

       public:

       Rectangle();

       Rectangle(double newLength, double newWidth);

       void setLength(double l);

       void setWidth(double w);

       double getLength();

       double getWidth();

       double computeArea();

       double computePerimeter();

       

       Rectangle operator++ ();

       Rectangle operator++ (int);

       

       Rectangle operator-- ();

       Rectangle operator-- (int);

       Rectangle operator- (Rectangle r);

       bool operator== (Rectangle r);

       bool operator!= (Rectangle r);

       

       void printDetails();

};

           main.cpp

#include "Rectangle.h"

       // Ask the user to type in a length and width and

       // create an object called rect2 of the rectangle class

       // See output for format

       cout << "Enter the length of rectangle 3: ";

       cin >> l;

       cout << "Enter the width of rectangle 3: ";

       cin >> w;

       Rectangle rect3(l, w);

       cout << endl;

       cout.setf(ios::fixed);

       cout.precision(1);

       // Using the member function in the class, print rect1, rect2,

       // and rect3 details in that order

       rect1.printDetails();

       rect2.printDetails();

       rect3.printDetails();

       cout << endl;

       // Print each rectangle in the format shown on the output

       cout << "Rectangle 1: " << rect1.getLength() << " X " << rect1.getWidth() << endl;

       cout << "Area: " << rect1.computeArea() << " Perimeter: " << rect1.computePerimeter() << endl;

       cout << "Rectangle 2: " << rect2.getLength() << " X " << rect2.getWidth() << endl;

       cout << "Area: " << rect2.computeArea() << " Perimeter: " << rect2.computePerimeter() << endl;

       cout << "Rectangle 3: " << rect3.getLength() << " X " << rect3.getWidth() << endl;

       cout << "Area: " << rect3.computeArea() << " Perimeter: " << rect3.computePerimeter() << endl;

       if(rect2 == rect3) {

               cout << "rectangle 2 and 3 are same." << endl;

       } else {

               cout << "rectangle 2 and 3 are not same." << endl;

       }

       cout << "After incrementing rectangle 2: ";

       rect2++;

       rect2.printDetails();

   return 0;

}

Step-by-step explanation: Notice that the figure shown here is a rectangle so we can find its area by using the formula length x width.

Since the length is 3/7 in and the width is 2/8 in, we can plug this information into the formula to get (3/7)(2/8).

Now multiplying across the numerators and multiplying across the denominators we get 6/56 which can be reduced to 3/28 in².

Step-by-step explanation: Notice that the figure shown here is a rectangle so we can find its area by using the formula length x width.

Since the length is 3/7 in and the width is 2/8 in, we can plug this information into the formula to get (3/7)(2/8).

Now multiplying across the numerators and multiplying across the denominators we get 6/56 which can be reduced to 3/28 in².



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