Let's say the sodas are each $1. If you have purchased 4 sodas it will cost $4. You still have $5 left on your bill. If you have 2 hamburgers left on your bill the amount of each hamburger is $2.50.

Let the cost of soda be s.

Let the cost of hamburgers = h

Multiply Equation (1) by 2 :

Equation (1) - (2):

1 hamburger costs $2.50

Let the cost of hamburgers = h

Multiply Equation (1) by 2 :

Equation (1) - (2):

1 hamburger costs $2.50

Let the cost of one soda be $x

and let the cost of one hamburger be $y

Since, 2 sodas and 4 hamburgers cost $12.00

So,

2x+4y = 12

Dividing the whole equation by 2, we get

x+2y= 6 (equation 1)

Now, 4 sodas and 2 hamburgers costs $9.00

4x+2y=9 (equation 2)

Substituting the value of 'x' from equation 1 in equation 2, we get

4(6-2y)+2y = 9

24-8y+2y=9

24 - 6y = 9

24 - 9 = 6y

15 = 6y

y = 2.5

So, the cost of one hamburger is $2.5

2.00 cause the pops are 1.25 × that by 4 it's 5.00 add the 4.00 for the burgers and it's 9.00

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