To find the smallest y-value, you substitute x=0 into each other the functions.

For function a(x), do a(0):

a(0) = (0+5)2-7 = 3

For function b(x), it gives you (0,6).

For function c(x), just look at where the line crosses the x-axis. It crosses it as -2, and there's a point at (0,-2).

So since -2 is the smallest, function c(x) has the smallest y-intercept: -2

For function a(x), do a(0):

a(0) = (0+5)2-7 = 3

For function b(x), it gives you (0,6).

For function c(x), just look at where the line crosses the x-axis. It crosses it as -2, and there's a point at (0,-2).

So since -2 is the smallest, function c(x) has the smallest y-intercept: -2

A.

Step-by-step explanation:

A quadratic function may only intercept the y-axis once. This is because the definition of a y-intercept tells us that it is the point where x = 0. If there are multiple points where x = 0, then the expression cannot be a function. As such, a quadratic function can only have one.

Choice B contradicts the previous statement.

Choice C is wrong because the x-intercept is the zero of the function. This is because at a given x-coordinate that touches the x-axis, the y-coordinate will be 'zero'.

Choice D is wrong because the y-intercept is where x = 0.

I hope this helps!

1)

2) and

3) (0,12)

4)

Step-by-step explanation:

The function represents the height (h) of the ball after t seconds.

Find the vertex of the parabola:

Hence, the vertex of the function is at point

The axis of symmetry of the function is vertical line which passes through the vertex, so its equation is

To find y-intercept, equat t to 0 and find h:

Hence, y-intercept is at point (0,12)

To find the roots of the quadratic finction, equate h to 0 and solve the equation for t:

Therefore, two roots are and

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