In a school one-third of all 240 students play soccer. forty four students play both soccer and basketball and sixty students do not play any of these games. how many students play only basketball?


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step-by-step explanation:

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Write a paragraph proof! ! 20 points and will give brainliest

i think it's either c or d

step-by-step explanation: the entire question is extremely odd. 04 obviously refers to the interest rate. honestly i will say the answer is c. because the (2 x 12) part would mean it's compounded semiannually. i'll say choose c.

Someone i retook this test twice already

100 students play only basketball.            

Step-by-step explanation:

We are given the following information in the question:

Total number of students in school = 240

Number of students that play soccer =

\dfrac{1}{3}\times \text{Total number of students}\\\\=\dfrac{1}{3}\times 240 = 80

n(S) =80

n(S\cap B) = 44

n(S'\cap B') = 60


n(S\cup B) = \text{Total} - n(S' \cap B')\\n(S\cup B) = n(S) + n(B) - n(S\cap B)

Putting the values, we get,

n(S\cup B) =240-60=180\\n(S\cup B) = 180 = 80 - 44 + n(B)\\n(B) = 180 - 80 + 44= 144

Thus, 144 students play  basketball.

Out of these 144, 44 plays soccer as well.

\text{Student only playing basketball} = 144 -44 = 100

Thus, 100 students play only basketball and not soccer.

Do you know the answer?

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