infinitely manyone solutionno solutionone solution

Step-by-step explanation:

1. 4x−x=2x+x

Simplifies to 3x = 3x, which is true for all values of x. Hence there are infinitely many solutions.

___

2. 2x+1=5

True only for x=2; one solution.

___

3. 4x+2=5x−x+4

Simplifies to ...

4x +2 = 4x +4

2 = 4 . . . . . . . not true for any value of x; no solution.

___

4. 2(x+4)=4(x+2)

Simplifies to ...

2x +8 = 4x +8

0= 2x . . . . . . . . . subtract 2x+8

True only for x=0; one solution.

Step-by-step explanation:

1) 8(a + 2) = 5a +16 + 3a.

8a + 16 = 8a +16

8a - 8a = 16 - 16

So, one solution a =0

2)6m + 2 – 4m = 2(m + 2)

2m + 2 = 2m + 4

so, no solution.

3) 3(z + 3) = 7 + 3z + 6 - Z

3z + 9 = 13 +2z

3z - 2z = 13 - 9

z = 4

So, one solution

Once put into the quadratic formula the numbers in the square root of they are negative no solutions if it is 0 then 1 solution if more then more than one solution

no solutions

Step-by-step explanation:

-2(11-12x)=-4(1-6x)

distribute

-22 +24x = -4 +24x

Subtract 24x from each side

-22+24x-24x = -4 +24x -24x

-22 = -4

This is never true, so there are no solutions

equation 1 has no solutions

Equation 2 has no solutions

Equation 3 has one solution

Idk if I'm 100% right tho

Step-by-step explanation:

The equation has one solution

Step-by-step explanation: First , open the brackets

7( 12 - 2x ) = 4 (3 - 3x )

84 - 14x = 12 - 12x

collect the like terms

84 - 12 = - 12x + 14x

72 = 2x

Therefore divide through by 2

x = 72/2

x = 36

Therefore, the equation has only one solution

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