The probability of the spinner landing on A is 0.1111.
The possible outcomes of a board game is that it can lead on any three of the regions, A, B and C.
The probability of all the outcomes of an event sums up to be 1.
According to the provided information:
P (B) = 3 P (A)
P (C) = 5 P (A)
Compute the probability of the spinner landing on A as follows:
Thus, the probability of the spinner landing on A is 0.1111.
The answer is D, 1/8
I chose 1/8 because there were 8 numbers and 1 five. If there were 3 numbers and 1 five, the answer would be 1/3.
probability = 5/10 = 1/2
P(red & red) = 0.5×0.6 = 0.3
P(blue & blue) = 0.5 × 0.4 = 0.2
84 = N(0.3)
N = 280
Expected no. of both blue:
280 × 0.2 = 56
To find the probability of both spinners landing on red, we need to multiply the probability of the spinner A landing on red (0.5) by the probability of the spinner B landing on red (0.6):
P(redA and redB) = 0.5 * 0.6 = 0.3
Then, to find the probability of both landing on blue, we do the same:
P(blueA and blueB) = 0.5 * 0.4 = 0.2
Now, if the number of times that both spinners land on red is 84, to estimate the number of times that both land blue, we just need to multiply this number of times by the ratio of P(blueA and blueB) over P(redA and redB):
84 * 0.2 / 0.3 = 56 times
Spinner AProbability of red = 0.5, Probability of blue = 0.5
Spinner BProbability of red = 0.6, Probability of blue = 0.4
Probability of both A and B land on red:0.5*0.6= 0.3
Number of attempts to get outcome of 84 red on both spinners is:84/0.3= 260
Probability of both spinners land on blue:0.5*0.4= 0.2
Estimated number of both spinners land on blue:260*0.2= 52
Let's call x the probability of landing in A
So, probability of landing on B is 5x and probability of landing on C is 3x.
As we only have this options, the probabilities A + B + C = 1. So,
x + 5x + 3x = 1
9x = 1
x = 1/9