< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

ac ≅ ab (given)< cax ≅ < bax (given)ax ≅ ax (common side)so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

ac ≅ ab (given)< cay ≅ < bay (since < cax ≅ < bax is given and xy is the extension of line ax)ay ≅ ay (common side)so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

the answer will be b x² +x-1

step-by-step explanation:

Ok jnibinubu y y y buy un u ibubibibu

answer: 25\pi\ ft^2 (first option)

step-by-step explanation:

the formula for calculate the area of a circle is the one shown below:

a=r^2\pi

where r is the radius of the circle.

xy is the diameter. then the radius is:

r=\frac{10ft}{2}\\r=5ft

substitute values into the formula shown above. therefore, the area of the circle is:

a=(5ft)^2\pi \\a=25\pi\ ft^2

~ i think hope dis

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