< xcy ≅ < xby
step-by-step explanation:
in δcax and δbax,
ac ≅ ab (given)< cax ≅ < bax (given)ax ≅ ax (common side)so, δcax ≅ δbax (side-angle-side or sas)
since δcax ≅ δbax, we can conclude < acx ≅ < abx
in δacy and δaby,
ac ≅ ab (given)< cay ≅ < bay (since < cax ≅ < bax is given and xy is the extension of line ax)ay ≅ ay (common side)so, δacy ≅ δaby (side-angle-side or sas)
since δacy ≅ δaby, we can conclude < acy ≅ < aby
now,
< acy ≅ < aby
=> < acx + < xcy ≅ < abx + < xby
=> < acx + < xcy ≅ < acx + < xby (since < acx ≅ < abx already proved above)
subtracting < acx from both sides, we get
< acx + < xcy -< acx ≅ < acx + < xby -< acx
cancelling out < acx and -< acx from both sides, we get
< xcy ≅ < xby (proved)
the answer will be b x² +x-1
step-by-step explanation:
answer: 25\pi\ ft^2 (first option)
step-by-step explanation:
the formula for calculate the area of a circle is the one shown below:
a=r^2\pi
where r is the radius of the circle.
xy is the diameter. then the radius is:
r=\frac{10ft}{2}\\r=5ft
substitute values into the formula shown above. therefore, the area of the circle is:
a=(5ft)^2\pi \\a=25\pi\ ft^2
~ i think hope dis