Eorigin. the points c, a, and b map to c, a', and
in the diagram, the circle will be dilated by a scale factor of 3 about the origin. the po
is the length of cb? use the distance formula to you decide: d = (x2 - x) +(y2 - y).
a = (8, 15)
b = (12, 13)
c = (8, 10)
to
é 4
6 8
10
12
14
16
a.
5 units
b.
15 units
c.
d.
21 units
24 units
45 units
e.
pls


Eorigin. the points c, a, and b map to c, a', and in the diagram, the circle will be dilated b

Answers

The correct answer to this is 12
Also, FG=(2)^2+(-4)^2
FG=4+16
FG=20
so see which ones end up with 20

not A
not B
not C
D is the answer

The length of DE is 10 units

Step-by-step explanation:

Find the length of DE using the distance formula.

(-4,2) (4,-4)

just did it.

Is there a picture included?

Step-by-step explanation:

First, find the distance AB by the formula:

AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}.

If A(0,-7) and B(8,8), then

AB=\sqrt{(8-0)^2+(8-(-7))^2}=\sqrt{8^2+15^2}=\sqrt{64+225}=\sqrt{289}=17.

Dilating polygon ABCD by a scale factor of 2 with the center of dilation at the origin to create polygon A′B′C′D′, you increase the distance AB twice, A'B'=2AB. Thus, A'B'=2·17=34 units.

AB=17 units, A'B'=34 units.

d   = √1156 units

Step-by-step explanation:

We have given end-points of AB.

(0,-7) and (8,8)

We have to find length of A⁰B⁰.

Scale factor is 2.

Hence, end-points of A⁰B⁰ are

2(0,-7) and 2(8,8)

(0,-14) and (16,16)

Hence, we can find length of A⁰B⁰ by using distance formula.

d   = √(x₂-x₁)²+(y₂-y₁)²

Putting values ,we have

d  = √(16-0)²+(16-(-14))²

d   = √(16)²+(16+14)²

d   = √256+900

d   = √1156 units which is the answer.

  D. FG^2 = 4^2 + 2^2

Step-by-step explanation:

Given: We can find the length of FG using the Distance Formula:

[Distance formula to find length of line from point (x_1,y_1) to point (x_2,y_2 is given by :-

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2})\\\\\Rightarrow d^2=(x_2-x_1)^2+(y_2-y_1)^2]

FG^2 =(3 - 1)^2 + (-1 - 3)^2

Since, 3-1=2 and -1-3=-(1+3)=-4

Therefore,  FG^2 =(2)^2 + (-4)^2=2^2+((4)(-1))^2=2^2+4^2(-1)^2=2^2+4^2

Hence, the formula also represents the length of FG is FG^2 = 4^2 + 2^2.

34

Step-by-step explanation:

The scale of factor is 2. Then, you must multiply the coordinates of the endpoints AB by 2 to obtain the coordinates od the enpoints A'B':

(0*2,-7(2))=(0-14)

(8*2,8*2)=(16,16)

Substitute values into the formula, then you obtain that the length A'B' is:

d=\sqrt{(16-0)^2+(16-(-14))^2}\\d=34



Do you know the answer?

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