number of cars x probability 0 1 2 3 4 5 6

0.07 0.31 0.43 0.12 0.04 0.02 0.01

a housing company builds houses with two-car garages. what percent of households have more cars than the garage can hold?

The mean would increase by 3

Step-by-step explanation:

The number cars and their probability is shown on the first uploaded image

The mean for the number of cars[X] owned can be mathematically represented as

From the question we are told that each household purchased additional three cars

Let Z be the random variable for the number of cars when the the additional car where added

So Mathematically

Z = X + 3

The mean for the number of cars[X + 3] owned can be mathematically represented as

From the above equation we can see that the mean would increase by factor of 3

19% of households have more cars than the garage can hold

Step-by-step explanation:

We are given the following distribution for the number of cars owned by a family.

Number of cars X: 0 1 2 3 4 5 6

Probability: 0.07 0.31 0.43 0.12 0.04 0.02 0.01

We have to find the percentage of households have more cars than the garage can hold.

A garage can hold two cars. Thus, the household with more than two cars are the households that have more cars than the garage can hold.

The given distribution is a discrete probability distribution.

Thus, we evaluate:

Thus, 19% of households have more cars than the garage can hold.

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