Adata set consists of the values 2, 6, 3, and 1. if we consider this a population (all the values available), the variance isa. 12
b. 14
c. the square root of 3.5
d. the square root of 14
e. none of the above

Answers

The standard deviation of the set of values (2, 3, 6, 9, 10) is square root of 12.5 (\sqrt{12.5}) therefore OPTION C
What is the standard deviation of the data set given below 2 3 6 9 10 a:  10 b:  square root of 10 c
The solution to this problem would be 4.71815739503
The answer should be 59160797.83

the answer is a on edgenunity

Step-by-step explanation:

Square root of 12.5

Step-by-step explanation:

How exactly is the square root written?

First of all, negative numbers will surely come before positive ones. So, let's compare -2.3 and -1/3.

One is a number, one is a fraction. You can either turn the fraction to number, or the number to fraction. The first option is surely easier: we have -1/3 = -0.333...

So, -1/3 is closer to 0 than -2.3, so we have  -2.3 < -\frac{1}{3}

As for the positive numbers, we have to order  \sqrt{7},\ \sqrt{3},\ 5.1 . When dealing with positive numbers, it is true that  x < y \implies x^2 < y^2 . So, we can square the numbers to get rid of the roots: we have

 3 = \sqrt{3}^2 < 7 = \sqrt{7}^2 < 26.01 = 5.1^2 .

So, the ordered list is the following:

 -2.3,\ -\frac{1}{3}, \sqrt{3},\ \sqrt{7},\ 5.1

Yek
-2.3, -1/3, square root of 3, square root of 7, 5.1

E. none of the above

Step-by-step explanation:

The given data values that represents the population:

2, 6, 3, and 1.

Number of values : n=4

Mean of the data values = \dfrac{\text{Sum of values}}{\text{No. of values}}

\dfrac{2+6+3+1}{4}=\dfrac{12}{4}=3

Sum of the squares of the difference between each values and the mean =

(2-3)^2+(6-3)^2+(3-3)^2+(1-3)^2

=-1^2+3^2+0^2+(-2)^2

=1+9+0+4=14

Now , Variance = (Sum of the squares of the difference between each values and the mean ) ÷ (n)

= (14) ÷ (4)= 3.5

Hence, the  variance is 3.5.  

Therefore , the correct  answer is "E. none of the above".



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