Line segment ba has endpoints b(-6,3) and a(-1,8). what are coordinates of the point located 1/5 of the way from b to a

Answers

\vec C = (-5,4)

Step-by-step explanation:

The coordinates of the point located 1/5 of the way from B to A is:

\vec C = \vec B + \alpha \cdot \overrightarrow {BA}

\vec C = (-6,3) + \frac{1}{5}\cdot (-1+6,8 - 3)

\vec C = (-6,3) + \frac{1}{5}\cdot (5,5)

\vec C = (-6,3) + (1,1)

\vec C = (-6+1,3+1)

\vec C = (-5,4)



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