Which statements about the graph of the function f(x) = 272
- x-6 are true? select two options,
the domain of the function is xix2
the range of the function is all real numbers
the vertex of the function is 4-6
the function has two x-intercepts
the function is increasing over the interval (-6

Comlement is the angle that adds to 90
supplement is the one that adds to 180

x+c=90
x+s=180

solving for s and c
minus x frmo both sides in both equations
c=90-x
s=180-x

c(x)=90-x
s(x)=180-x

the domain has to be the numbers that make c(x) positive (assuming you haven't taken trig)
also, the angle cannot be negative
so x>0
solve for where it equal 0
for c(90) that is the zero and s(180) is the other zero

range is from 0 to the end

c(x)=90-x
domain is from 0 to 90
range is from 0 to 90

s(x)=180-x
the domain is from 0 to 180
range is from 0 to 180

What is the function

f(x) = 2x / (3x^2 - 3)

???

Domain: R \ {-1 ; 1}

Range: R

The domain of a function is the set of all the x terms of the function and the range of a function is the set of all the y terms of a function.

For example, take a look below.

The domain is the set of all x terms in each ordered pair and the

range will be the set of all the y terms in each ordered pair.

Step-by-step explanation:

The vertex can be located most easily by completing the square of

f(x) = -X^2 - 2x - 1 (which is equivalent to -(x^2 + 2x + 1).  The latter expression can be rewritten as -(x + 1)^2, which indicates that the x-coordinate of the vertex is -1.  The corresponding y-value is 0.  Vertex is at (-1, 0).

The function is increasing for x < -1 and decreasing for x > -1.

The domain of the function is "all real numbers."

The range is (-infinity, 0)

Step-by-step explanation:

Given is a function as

We find that this funciton is undefined for denominator =0

Denominator =0 when

Hence function is not defined for x=1,-1

Domain is R-{-1,1}

To find range:

We see that denominator has degree 2 and numerator degree 1

i.e. denominator has more degree of x then numerator

Hence y=0 is horizontal asymptote

But when y=0 we have x=0

Hence though there is a horizontal asymptote range is the set of all real numbers

Domain = R-{-1,1}

Range = R

RANGE: {20.8, 22.4, 25.2, 26.8, 28.4} goes with DOMAIN: {52, 56, 63, 67, 71}

RANGE: {16, 18, 20, 22,24} goes with DOMAIN: {40, 45, 50, 55, 60}

RANGE: {17.6, 20.4, 23.6, 26.4, 29.2} goes with DOMAIN: {44, 51, 59, 66, 73}

RANGE: {14.8, 18.4, 19.6, 22, 22.8} goes with DOMAIN: {37, 46, 49, 55, 57}

Step-by-step explanation:

Range : {11,27,43,59}

Step-by-step explanation:

Given:

f(x) = 4x - 1

Domain : {3,7,11,15}

f(3) = 4(3) -1 = 11

f(7) = 4(7) -1 = 27

f(11) = 4(11) -1 = 43

f(15) = 4(15) -1 = 59

hence Range : {11,27,43,59}

Domain: [0,8]

Range: {50,100,200}

Step-by-step explanation:

Domain: It is input value of x where function is well defined.

Range: It is output value of y.

Domain is on x-axis that is cleaning time in hours.

We can see in graph cleaning time start from 0 and end at 8

Domain should be 0 to 8

Domain: [0,8]

For range we see the y value that is Total cost in $.

For x, 0 to 2 , y value is constant.

For time , 0 to 2, Cost is constant. Therefore, Range = 50

For time , 2 to 6, Cost is constant. Therefore, Range = 100

 For time , 6 to 8, Cost is constant. Therefore, Range = 200

Range: {50,100,200}

D:   {9, 21, 33}

Step-by-step explanation:

Ken worked 2, 8 and 14 hours on 3 separate days.

For working 2 hours, his earnings were f(2) = 2(2) + 5, or 9;

For working 8 hours, his earnings were f(28) = 2(8) + 5, or 21; and

For working 14 hours, his earnings were f(14) = 2(14) + 5, or 33

Thus, the range of this function for the days given is {9, 21, 33} (Answer D)

D. The functions have the same range

Step-by-step explanation:

Plot both functions using technology.

The both intersect the x-axis at x = 0 and the y-axis at y = 0.

The domain for both is all reals.

The range of g(x) is all reals since when you cube a negative you get negative.

The range of f(x) is all non-negative number since the square of a negative is positive.

D. The functions have the same range