Aline has a slope of -4/5 which ordered pairs could be points on a line that is perpendicular to this line?

Answers

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Asap !  giving brainliest !   a line has a slope of -4/5. which ordered pairs could be points on a l

The first pair (-2,0) and (2,5) and the last pair (2,-1) and (10,9)

Step-by-step explanation:

The perpendicular line has what is called a 'negative reciprocal slope'. This means you have to calculate -1 divided by the original slope.

For your line with slope -4/5, we're looking for a line with slope -1/(4/5) = 5/4.

Now we have to calculate the slope of each of the given pairs to find a match. We do this by dividing the y difference by the x difference.

(-2,0) and (2,5) -> slope is (5-0)/(2--2) = 5/4 Match!!

(-4,5) and (-3,4) -> slope is (4-5)/(-3--4) = -1/1 = -1 No match

(-3,4) and (2,0) -> slope is (0-4)/(2--3) = -4/5 No match

(1,-1) and (6,-5) -> slope is (-5--1)/(6-1) = -4/5 No match

(2,-1) and (10,9) -> slope is (9--1)/(10-2) = 10/8 = 5/4 Match!!

So the first and the last pairs are on perpendicular lines (not necessarily the same lines, as there are infinite possible perpendicular lines)

The answer is A and E

Step-by-step explanation:

Step-by-step explanation:

Given that a  line has a slope of \frac{-4}{5}

For any line perpendicular to this line,

the slope of the line = \frac{-1}{slope of the given line} \\=\frac{-1}{\frac{-4}{5} } \\=\frac{5}{4}

Let us check whether the given options satisfy this

a) (-2,0) and (2,5)... slope = \frac{5-0}{2-(-2)} =\frac{5}{4}

Yes true

b) (–4, 5) and (4, –5)... slope = \frac{-5-5}{4-(-4)} =\frac{-5}{4}

No not true.

c) (–3, 4) and (2, 0)

Slope = \frac{-4}{5}

No not true.

d) (1, –1) and (6, –5)

Slope = \frac{-5+1}{6-1} =\frac{-4}{5}

No, not true.

e) (2, –1) and (10, 9)

Slope = 5/4

True.

e) (2, –1) and (10, 9)

Options A and Option E.

Step-by-step explanation:

A line has a slope of -4/5. Now a line perpendicular to this line will have the slope as m_{1}.m_{2}=-1

Therefore m_{2}=-\frac{1}{m_{1}}=\frac{1}{\frac{4}{5} }=\frac{5}{4}

Now we will find the slope with the help of points given in the options if they lie on the perpendicular line.

A). m=\frac{5-0}{2+2}=\frac{5}{4}

B). m=\frac{-5-5}{4+4}=\frac{-10}{8}=-\frac{5}{4}

C). m=\frac{0-4}{2+3}=-\frac{4}{5}

D). m=\frac{-5+1}{6-1}=\frac{-4}{5}=-\frac{4}{5}

E). m=\frac{9+1}{10-2}=\frac{10}{8}=\frac{5}{4}

Options A and E are the correct options.

C

Step-by-step explanation:

=(0-4)/(2+3)

=-4/5

A and E

Step-by-step explanation:

A line has a slope of -4/5, then a perpendicular line has a slope 5/4, because

-\dfrac{4}{5}\cdot \dfrac{5}{4}=-1

Find the slopes of the lines in all options:

A. True

\dfrac{5-0}{2-(-2)}=\dfrac{5}{4}

B. False

\dfrac{-5-5}{4-(-4)}=-\dfrac{5}{4}

C. False

\dfrac{0-4}{2-(-3)}=-\dfrac{4}{5}

D. False

\dfrac{-5-(-1)}{6-1}=-\dfrac{4}{5}

E. True

\dfrac{9-(-1)}{10-2}=\dfrac{5}{4}

options A & E

Step-by-step explanation:

Im pretty sure it answer options 1 and 5

Step-by-step explanation: 1) (-2,0) and (2,5)      5) (2,-1) and (10,9)

its on edg.



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