Arectangular box is 10 in. ​wide, 10 in. ​tall, and 8 in. long. what is the diameter of the smallest circular opening through which the box will​ fit?

Answers

I’d say letter a..
Which complex number is represented by the pointe graft on the complex plane below? a. -4+3i b. 3+4

yep

step-by-step explanation:

Diameter of smallest circular opening = 12.81 in

Step-by-step explanation:

Given:-

Width of rectangular box(W)=10 in.

Length of rectangular box(L)=8 in.

Height of rectangular box(H)=10 in.

For box to fit in the smallest circular opening we need to find the diagonal of the rectangular box, therefore

diagonal of rectangular box=diameter of smallest circular opening

So,

Diagonal\ (d)=\sqrt{width^{2}+length^{2}  }

d=\sqrt{W^{2} +L^{2} }

d=\sqrt{10^{2}+8^{2}}

d=\sqrt{100+64}

d=\sqrt{164}

d=12.81\ in.

\therefore\ diagonal\ (d)=12.81\ in

Therefore diameter of smallest circular opening = 12.81 in.



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