, 15.09.2019heyitseddie06

# The function below models the voltage, in volts, of a certain alternating current after x seconds, where a and b are positive constants. f(x) = acos(bx) assume the expression inside the cosine function is measured in radians. what is the largest value of c such that when the voltage's domain is restricted to the interval [0,c], the function is invertible ninaaforever

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb lizdeleon248

can i see the following ?

step-by-step explanation: ajbrock1004

First of all, we can just ignore A, it has no effect but to vertically stretch our cosine.

If it was only , the function would be invertible as long as it's confined between and . Now, the argument of our cosine is not but . It means that it won't stop at , but at .

Another way to think about it, "what should i replace x with so I get inside the cosine?"  ### Other questions on the subject: Mathematics Mathematics, 21.06.2019, joshsd8479 Mathematics, 21.06.2019, cassie2021
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