Find the area between y=e^x and y=e^2x over [0,1]

Answers

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .

kkkll

step-by-step explanation:

kljlklj

Step-by-step explanation:

Just so you see what you are trying to do, the graph shows you what you are given.

Graph

Red: y = e^x

blue: y = e^(2x)

green x = 1

equations

integral e^(2*x) = e^(2x)/2

integral e^x = e^x

Solution

e^(2x)/2 between 1 and 0 equals e^(*2*1)/2 - e^0

e^(2x) / 2 = 7.3891 - 1 = 6.3891

e^(x )  between 1 and 0 equals e^(1) - e^0

2.7183 - 1

1.7183

The area between 1 and 0 is 6.3891 - 1.7183 = 4.6708


Find the area between y=e^x and y=e^2x over [0,1]


Do you know the answer?

Other questions on the subject: Mathematics

Mathematics, 22.06.2019, ella3714
Area = 1/2 (Base) (Height)Area = 1/2 (12 in) (8 kn) Area = 1/2 (96 in)Area = 48 in^2Volume = (Area) (Length)Volume = (48 in^3) (13 in)Volume = 624 in^3...Read More
3 more answers