Two cars leave town 400 kilometers apart at the same time and travel each other one car rate is 12 km/h less than the others if they me in two hours what is the rate of the slower car

time is equal to distance over rate so

t = d/r

need a little bit more information for the second question.

hi! all you have to do is add 3 to both sides of the equation.

3 + -3 + a < -7 + 3

a < -4

hope this you!

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.