On a coordinate grid, the coordinates of vertices p and q for polygon pqrs are p(1, 2) and q(−1, 2). what is the length of side pq of the polygon?
2 units
3 units
4 units
6 units

Answers

We need to use the distance formula here
d = \sqrt{(x_2 - x_1)^2+(y_2-y_1)^2}
Now, substitute in the points (1, 2) and (-4, 2)
d = \sqrt{(-4-1)^2 + (2-2)^2}
Simplify
d = \sqrt{(-5)^2 + 0^2}
d = \sqrt{25}
d = 5

The correct option is 4.

Step-by-step explanation:

Given information: P(1,2) and Q(-4,2)

We need to find the length of side PQ of the polygon.

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula we get

PQ=\sqrt{(-4-1)^2+(2-2)^2}

PQ=\sqrt{(-5)^2+(0)^2}

PQ=\sqrt{25}

PQ=5

The length of side PQ of the polygon is 5 units. Therefore the correct option is 4.

Step-by-step explanation:

its 6 i hope this helps

3 units

Step-by-step explanation:

2 units

Step-by-step explanation:

Polygons are shapes with straight sides and must be closed. Also, polygons sides never touch. Polygons are classified according to its number of sides. Since in this problem we have four points because the polygon is PQRS, then this is a Quadrilateral, which is any polygon with exactly 4 sides. We only know two points P(1, 2) and Q(−1, 2). To find the length of Side PQ of the polygon we must use the distance formula:

d=\sqrt{(x_{1}-x_{2})^2+(y_{1}-y_{2})^2}

If \ P(1, 2)=P(x_{1},y_{1}) \ and \ Q(-1, 2)=Q(x_{2},y_{2}) \ then: \\ \\ d=\sqrt{(1-(-1))^2+(2-2)^2} \\ \\ \boxed{d=2}

Finally, the length of Side PQ of the polygon is 2 units

2 units

Step-by-step explanation:

Polygons are shapes with straight sides and must be closed. Also, polygons sides never touch. Polygons are classified according to its number of sides. Since in this problem we have four points because the polygon is PQRS, then this is a Quadrilateral, which is any polygon with exactly 4 sides. We only know two points P(1, 2) and Q(−1, 2). To find the length of Side PQ of the polygon we must use the distance formula:

d=\sqrt{(x_{1}-x_{2})^2+(y_{1}-y_{2})^2}

If \ P(1, 2)=P(x_{1},y_{1}) \ and \ Q(-1, 2)=Q(x_{2},y_{2}) \ then: \\ \\ d=\sqrt{(1-(-1))^2+(2-2)^2} \\ \\ \boxed{d=2}

Finally, the length of Side PQ of the polygon is 2 units



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