, 22.06.2019hannahpalacios101

# 36x2 + 49y2 = 1,764 the foci are located at: a) (-√13, 0) and (√13,0) b) (0, -√13) and (0,√13) c) (-1, 0) and (1, 0)

4pounds of live bait and 1 pound of natural bait

i think it is 18

step-by-step explanation:

The answer is A) (-√13, 0) and (√13,0)

Step-by-step explanation:

Given equation is 36x^2 + 49y^2 = 1,764

We have to find the foci

The above equation can be written as

This equation is of the form of ellipse whose standard equation can be written as

where a  represents the radius of the major axis and b  represents the radius of the minor axis of the ellipse.

By comparing the above two equations, we get

a=7, b=6, h=0 and k=0

The foci of ellipse are (h+c,k) and (h-c,k)

c is the distance from the center to a focus which can be calculated as

Substitute the values to find foci, we get

and

and

Option (A) is correct.

Foci of given equation located at  (-√13, 0) and (√13,0)

Step-by-step explanation:

Consider the given equation

We have to find the foci for the above equation,

First divide whole equation by 1764,

Since, both terms are positive so it is an equation of ellipse, a > b,

So it is a horizontal ellipse,

With center at (h , k ) and foci ( h±c, k)  where,

Given equation ,

,

Comparing a= 7 , b = 6 , h = k = 0

thus c = ±√13

Thus, foci is ( h±c, k) =  (0 ±√13 ,0)

Thus, Foci of given equation located at  (-√13, 0) and (√13,0)

Thus, option (A) is correct.

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