The velocity of a particle is v={2i+(6−2t)j} m/s, where t is in seconds. part a) if r = 0 when t = 0, determine the displacement of the particle during the time interval t = 2 s to t = 4 s .
The displacement of the particle in the time interval 5 seconds to 8 seconds will be 1.5 meters. Displacement is a vector quantity; meaning it has both magnitude and direction; magnitude being the distance between the interval at 5 seconds and position at 8 seconds, while the direction is from position at 5 second to position at 8 second. This is irrespective of the route followed during the time interval.
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