The velocity of a particle is v={2i+(6−2t)j} m/s, where t is in seconds.
part a) if r = 0 when t = 0, determine the displacement of the particle during the time interval t = 2 s to t = 4 s .

Answers

The displacement of the particle in the time interval 5 seconds to 8 seconds will be 1.5 meters. 
Displacement is a vector quantity; meaning it has both magnitude and direction; magnitude being the distance between the interval at 5 seconds and position at 8 seconds, while the direction is from position at 5 second to position at 8 second. This is irrespective of the route followed during the time interval.
The displacement is the vector with

magnitude
     distance between position at 5 sec and position at 8 sec
and direction
     direction from position at 5 sec to position at 8 sec .

The route followed during the time interval is irrelevant.

      
Magnitude
     distance between position at 5 sec and position at 8 sec
and direction
     direction from position at 5 sec to position at 8 sec .

The route followed during the time interval is irrelevant.

If you're doing PLATO the answer is 1.5 meters.

A. 160 meters

B. 80 meters

C. 40 meters

D. 20 meters

E. 0 meters

The correct answer is letter E. 0 meters.

Explanation:

A. 0 meters

Explanation:

1.5

Explanation:

1.5 meters plato users ;)

Explanation:

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